Answer:

Step-by-step explanation:
For 1 Quarter:

For 5 Quarter:

Answer:
- <u>59.0891 g (rounded to 4 decimal places)</u>
Explanation:
<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.
Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:
Where:
- A is the amount that remains of the substance after n half-lives have elapses, and
- A₀ is the starting amount of the substance.
In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:
- 330 days / 138 days = 2.3913
Therefore, the amount of polonium-210 that will be left in 330 days is:
Answer:
Step-by-step explanation:
just simplify the LHS first.
You can either multiply 1/5 by (x+3) and then solve
or
multiply both sides by 5 to get rid of 1/5 on LHS
I will multiply by 5
(x+3)= -10x-15 ( 5*1/5(x+3)= -5(2x+3)
now rearrange the equation
x+3=-10x-15
-10x-15-x-3=0
-11x-17=0
-11x=17
x= -17/11
Answer:
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If a woman making $45 an hour gets a 10% eaise how much additional money is she making.
$4.5
45 x .1 = 4.5