Question

3!+0!/2!*1! = 3/2 3 7/2

Answer 1

Answer:

$\large\boxed{\dfrac{7}{2}}$

Step-by-step explanation:

$n!=1\cdot2\cdot3\cdot...\cdot n\\\\3!=1\cdot2\cdot3=6\\0!=1\to\text{from de}\text{finition}\\2!=1\cdot2=2\\1!=1\\\\\dfrac{3!+0!}{2!\cdot1!}=\dfrac{6+1}{(2)(1)}=\dfrac{7}{2}$