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|First of all, the triangles are equal by ASA the way the diagram has been marked.
B and E are both right angles.
Side BC = Side DE
<BCA =< EDA
So triangle BCA = triangle EDA
Now to the letters.
x = y - 1 Add 1 to both sides.
x + 1 = y (1)
3x - 2 = 2y + 1 Subtract 1 from both sides.
3x -2 - 1 = 2y
3x - 3 = 2y Divide by 2
3x/2 - 3/2 = 2y/2
1.5x - 1.5 = y (2)
Step One
Since (1) and (2) both have y isolated on their respective right sides, they can be equated.
1.5x - 1.5 = x + 1 Take an x from both sides.
0.5x - 1.5 = x - x + 1
0.5x - 1.5 = 1 Add 1.5 to both sides.
0.5x = 1 + 1.5
0.5x = 2.5 Divide 0.5 on both sides.
0.5x/0.5 = 2.5/0.5
x = 5
Now we need a y value.
x = y - 1
5 = y - 1 Add 1 to both sides.
5 + 1 = y - 1 + 1
6 = y
So the 2 sides and the 2 angles are equal when
x = 5
y = 6
C Answer <<<<<<
Answer:
The expected participation rate is 0.637.
The standard error is 0.04397
Step-by-step explanation:
For each working age people asked, there are only two possible outcomes. Either they are in the labor force, or they are not. This means that we can solve this problem using binomial distribution probability concepts.
Binomial probability:
Expected value for the participation rate: The expected value is the probability of a success. In this problem, a success is a working age people being in the labor force. 63.7% of them are. So 
. This means that the expected participation rate is 0.637.
Standard error for the participation rate:
The standard error is given by the following formula:
.
In this problem, 120 people are asked, so 
.
So the standard error is 0.04397
($16.25×40)+($16.25×1.5×3)= $650 + 73.13 = $723.13
*regular hrs *overtime hrs
**multiplying the regular wage of $16.25 times 1.5 gives you the overtime, or time and a half, rate.
