The Least Common Multiple (LCM) will calculate when they are watered on the same day.
LCM of 4 and 7 is 28.
Answer: They will be watered together every 28 days.
https://www.steilacoom.k12.wa.us/cms/lib4/WA01001786/Centricity/Domain/490/Probability%20Notes%20Answers.pdf
this should have every thing on it hope it helps
Using Laplace transform we have:L(x')+7L(x) = 5L(cos(2t))sL(x)-x(0) + 7L(x) = 5s/(s^2+4)(s+7)L(x)- 4 = 5s/(s^2+4)(s+7)L(x) = (5s - 4s^2 -16)/(s^2+4)
=> L(x) = -(4s^2 - 5s +16)/(s^2+4)(s+7)
now the boring part, using partial fractions we separate 1/(s^2+4)(s+7) that is:(7-s)/[53(s^2+4)] + 1/53(s+7). So:
L(x)= (1/53)[(-28s^2+4s^3-4s^2+35s-5s^2+5s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]L(x)= (1/53)[(4s^3 -37s^2 +40s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]
denoting T:= L^(-1)and x= (4/53) T(s^3/(s^2+4)) - (37/53)T(s^2/(s^2+4)) +(40/53) T(s^2+4)-(4/53) T(s^2/s+7) +(5/53)T(s/s+7) - (16/53) T(1/s+7)
Answer:
4x+12
Step-by-step explanation:
Answer:
4 miles
Step-by-step explanation:
In order to find how many miles the car will travel in 0.5 hours, we can set up a proportion.
We can now cross multiply to find the value of x.
So the car can travel 4 miles in 0.5 hours.
Hope this helped!
