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Delvig [45]
3 years ago
7

1. The thin top layer of the crust is called the Crust. What are the two types of

Physics
2 answers:
kolbaska11 [484]3 years ago
8 0
Oceanic and continental
kupik [55]3 years ago
3 0

Answer:

I believe it's D

Lithosphere and Mantle

Explanation:

The Earth's crust is a thin shell on the outside of the Earth, accounting for less than 1% of Earth's volume. It is the top component of lithosphere: a division of Earth's layers that includes the crust and the upper part of the mantle.[9] The lithosphere is broken into tectonic plates that move, allowing heat to escape from the interior of the Earth into space.

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a cyclist applies a constant forward force of 20 N to maintain a velocity 2.5 m/s. how much power does the cyclist deliver?
forsale [732]

The power exerted by the cyclist is determined as 50 W.

<h3>Average power exerted by the cyclist</h3>

The power exerted by the cyclist is calculated as follows;

P = FV

where;

  • F is the applied force
  • V is velocity

P = 20 x 2.5

P = 50 W

Thus, the power exerted by the cyclist is determined as 50 W.

Learn more about power here: brainly.com/question/25263760

#SPJ1

4 0
2 years ago
Which of Galileo's observations directly disproved Ptolemy's epicycle model of the Solar System, showing that the Sun is at the
Neporo4naja [7]

Answer:

Venus observation.

Explanation:

Galileo had learned regarding the  heliocentric (Sun-centered) idea of Copernicus, and acknowledged it. However, the theory was proven by Galileo's observations of Venus. Galileo concluded that Venus should travel round the Sun, sometimes passing behind and then beyond, instead of directly rotating around the Earth.

8 0
3 years ago
While a block slides forward 1.35 m, a force pulls back at a 135 direction, doing -17.8 J of work. what is the magnitude of the
Mademuasel [1]
<h2>18.6467 N</h2>

Explanation:

       The Work done by any force is defined as the force applied times the displacement of point of application of force in the direction of force.

       This is better represented as a scalar product of Force vector and displacement vector.

       Work\textrm{ = }\vec{F}.\vec{s}

Here, the angle between force and displacement is 145^{o}.

       Work=|F||s|\cos\theta

       -17.8\textrm{ J = }|F|\times 1.35\textrm{ }m\times cos(135^{o})

       |F|=18.6467N

∴ Magnitude of force = 18.6467N

3 0
3 years ago
An object has a mass of 10grams and a volume of 20m3. what is the density of the object​
Pavlova-9 [17]

Explanation:

density = mass/ volume

in the question the mass is given in grams so will convert it into kg,

10 g = 0.01 kg

density= 0.01/ 20 = 1 / 2000 = 0.005 kg/m^3

7 0
3 years ago
A 1250-kg compact car is moving with velocity v1 =36.2i^+12.7j^m/s. It skids on a frictionless icy patch and collides with a 448
MA_775_DIABLO [31]

Momentum is conserved, so the sum of the separate momenta of the car and wagon is equal to the momentum of the combined system:

(1250 kg) ((36.2 <em>i</em> + 12.7 <em>j </em>) m/s) + (448 kg) ((13.8 <em>i</em> + 10.2 <em>j</em> ) m/s) = ((1250 + 448) kg) <em>v</em>

where <em>v</em> is the velocity of the system. Solve for <em>v</em> :

<em>v</em> = ((1250 kg) ((36.2 <em>i</em> + 12.7 <em>j </em>) m/s) + (448 kg) ((13.8 <em>i</em> + 10.2 <em>j</em> ) m/s)) / (1698 kg)

<em>v</em> ≈ (30.3 <em>i</em> + 12.0 <em>j</em> ) m/s

7 0
3 years ago
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