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Bond [772]
2 years ago
12

2h 10min expressed in seconds? Step by step please

Physics
2 answers:
Mice21 [21]2 years ago
4 0

Answer:

The answer is 7800 seconds

Explanation:

1 hour = 60 mins

2 hours = 120 mins (60×2)

120 mins + 10 mins = 130 mins

130min = 130 × 60 = 7,800 seconds

Sooo... 2 hr 10 min = 7,800 seconds

<em>hope this helps :D</em>

Scrat [10]2 years ago
3 0

Answer:

2 hour=2×60=120 min

2 hour+10 min =120+10=130 min

1 min=60 second

130 min=130×60=7,800 seconds

2 hour 10 min=7,800 seconds

Explanation:

Thanks!!!!!!

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7nadin3 [17]

Answer:

Gravity

Explanation:

It is gravity because the sun's gravity pulls all the planets towards itself and keeps the planets in the sun's orbit

8 0
2 years ago
If a boy (m = 25 kg) at rest on skates is pushed by another boy who exerts a force of 500 N on him and if the first boy's final
Bond [772]

Answer:

1 second

Explanation:

The impulse exerted on the boy is equal to its change of momentum:

I = \Delta p\\F \Delta t = m \Delta v

where

F = 500 N is the push on the boy

\Delta t is the contact time

m = 25 kg is the mass of the boy

\Delta v = 20 m/s is the change in velocity of the boy

Solving the formula for the contact time, we find

\Delta t=\frac{m\Delta v}{F}=\frac{(25 kg)(20 m/s)}{500 N}=1 s

7 0
3 years ago
How do inertia and centripetal force combine to keep an object moving in circular motion?
katen-ka-za [31]
As the centripetal force<span> acts upon an </span>object moving <span>in a </span>circle<span> at constant speed, the </span>force<span> always acts inward as the velocity of the </span>object<span> is directed tangent to the </span>circle. ... In fact, whenever the unbalanced centripetal force<span> acts perpendicular to the direction of </span>motion<span>, the speed of the </span>object will<span> remain constant.</span>
6 0
3 years ago
Read 2 more answers
a runner covers the last straight stretch of the race in 4 s. durning that time, he speeds up from 5 m/s to 9m/s what is the run
Sergio039 [100]

Answer:

The runner's acceleration was 1\ m/s^2

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

v_f=v_o+at

Solving for a:

\displaystyle a=\frac{v_f-v_o}{t}

The runner speeds up from vo=5 m/s to vf=9 m/s in t=4 seconds, thus:

\displaystyle a=\frac{9-5}{4}

\displaystyle a=\frac{4}{4}=1

The runner's acceleration was 1\ m/s^2

5 0
3 years ago
A robot is exploring​ charon, the dwarf planet​ pluto's largest moon. Gravity on charon is 0.278 meters per second ​[m divided b
DochEvi [55]

In order to find the efficiency first we will find the Change in Potential energy of the small stone that robot picked up

First we will find the mass of the stone

As it is given that stone is spherical in shape so first we will find its volume

V = \frac{4}{3}\pi r^3

V = \frac{4}{3}\pi *(\frac{0.06}{2})^3

V = 1.13 * 10^{-4} m^3

Now it is given that it's specific gravity is 10.8

So density of rock is

\rho = 10.8 * 10^3 kg/m^3

mass of the stone will be

m = \rho V

m = 10.8* 10^3 * 1.13 * 10^{-4}

m = 1.22 kg

now change in potential energy is given as

\Delta U = mgH

here

g = gravity on planet = 0.278 m/s^2

H = height lifted upwards = 15 cm

\Delta U = 1.22* 0.278 * 0.15

\Delta U = 0.051 J

Now energy supplied by internal circuit of robot is given by

E = Vit

V = voltage supplied = 10 V

i = current = 1.83 mA

t = time = 12 s

E = 10* 1.83 * 10^{-3} * 12

E = 0.22 J

Now efficiency is defined as the ratio of output work with given amount of energy used

\eta = \frac{\Delta U}{E}*100

\eta = \frac{0.051}{0.22} = 0.23

so efficiency will be 23 %

5 0
3 years ago
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