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Free_Kalibri [48]
3 years ago
13

State the restrictions on the domain.

Mathematics
1 answer:
mihalych1998 [28]3 years ago
8 0

we know that, denominator ≠ 0

16y² ≠ 0

y ≠ 0 is excluded value.

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The students in a class were each asked to name their favorite meal of the day. Which table could be represented by percentage b
sineoko [7]

Answer:

G

Step-by-step explanation:

I say G because when you look at the bar, the maximum is 100% and G is 20 in total. Therefore, the maximums are the same types and both can be divided by 10.

7 0
3 years ago
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Write the ratio of the first measurement to the second measurement. Compare in millimeters. Diameter of ball​ A: 44 mm diameter
Aneli [31]

Answer:

11:18

Step-by-step explanation:

Here, we are interested in calculating the ratio of diameter of ball A to that of ball B

what to do here is to ensure that both diameters have measurements that are same units.

Thus, mathematically;

44 mm to 7.2cm

But, mathematically;

10 mm = 1 cm

Thus 7.2cm = 7.2 * 10 = 72mm

Thus, our ratio becomes;

44:72

divide through be 4, we have

44/4 : 72/4

= 11 : 18

6 0
3 years ago
What is 23 + 23 - 789
Alex Ar [27]

Answer:

743

Step-by-step explanation:

23+23=46

789-46=743

4 0
3 years ago
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$650 is invested in an account at 3%
o-na [289]

Answer:

Step-by-step explanation:

Simple interest = 650*\frac{3}{100}=$19.5

End of first year = 650+19.5 = $669.50

End of second year = 669.50+19.5 = $ 689

End of third year = 689+19.5 = $708.50

End of fourth year = 708.50 +19.5 = $ 728

End of fifth year = 728 +19.5 = $747.50

8 0
4 years ago
How many 5 digit numbers are there whose digits sum to 39?
xenn [34]
The distribution of the possible digits of the numbers are
1.) 9, 9, 9, 9, 3  [Number of arrangements = 5! / 4! = 120 / 24 = 5]
2.) 9, 9, 9, 8, 4  [Number of arrangements = 5! / 3! = 120 / 6 = 20]
3.) 9, 9, 9, 7, 5  [Number of arrangements = 5! / 3! = 120 / 6 = 20]
4.) 9, 9, 9, 6, 6  [Number of arrangements = 5! / (3! x 2!) = 120 / 12 = 10]
5.) 9, 9, 8, 8, 5  [Number of arrangements = 5! / (2! x 2!) = 120 / 4 = 30]
6.) 9, 9, 8, 7, 6  [Number of arrangements = 5! / 2! = 120 / 2 = 60]
7.) 9, 9, 7, 7, 7  [Number of arrangements = 5! / (3! x 2!) = 120 / 12 = 10]
8.) 9, 8, 8. 8, 6  [Number of arrangements = 5! / 3! = 120 / 6 = 20]
9.) 9, 8, 8, 7, 7  [Number of arrangements = 5! / (2! x 2!) = 120 / 4 = 30]
10.) 8, 8, 8, 8, 7  [Number of arrangements = 5! / 4! = 120 / 24 = 5]

Number of 5 digit numbers whose digit sum up to 39 = 5 + 20 + 20 + 10 + 30 + 60 + 10 + 20 + 30 + 5 = 210
6 0
3 years ago
Read 2 more answers
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