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Phoenix [80]
2 years ago
13

Identify a set of parallel lines and a set of perpendicular lines in this image. Please help

Mathematics
1 answer:
ddd [48]2 years ago
4 0

Answer:

line AB and line CD are parallel

line AB and line EF are perpendicular

Step-by-step explanation:

it is the third option

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Which expression is equivalent to 2x^2 +7x+4
rodikova [14]

Answer:

11x + 4

Step-by-step explanation:

First find 2 to the power of 2. Which is multiplying 2 by its self so 4x.

Then add the 4x to 7x which is 11x

Then since 4 doent have an x it cant be combined so thats the answer: 11x + 4

6 0
3 years ago
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Please help its due in 1 hour it would be best if you show work
aleksley [76]

Answer:

1:quadrant 1

2:quadrant 1

3:quadrant 2

4:quadrant 3

5:quadrant 1

6:quadrant 4

7:Z and quadrant 2

8: F and quadrant 1

9:A and quadrant 4

10: R and quadrant 4

11: N and quadrant 2

12: Q and quadrant 3

13a:the clock

13b:wonder wheel

13c:big coaster

13d: -1,2

Good luck

6 0
2 years ago
Someone please help! I'm confused with c and d.
Karo-lina-s [1.5K]

It would be 3 times the sum of x and seven plus 10. This is because first you would would add 7+x (7x) and multiply it by 3. And then add on 10.

5 0
3 years ago
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Write 14:56 in its simplest form
OverLord2011 [107]

Answer:2:8

Step-by-step explanation:

divide everything by 7

4 0
3 years ago
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A debate team of 4 members for a high school will be chosen randomly from a potential group of 15 students. Ten of the 15 studen
iragen [17]

Answer:

A) 0.1538

Step-by-step explanation:

4 members are going to be chosen:

M1 - M2 - M3 - M4

We have to find the probability that for each member, one without experience is chosen. There is no replacents.

Initially, we have 15 students, of which 10 have none experience. So the probability that M1 is chosen as a student with no experience is \frac{10}{15}.

Then, there are 14 students, of which 9 have no experience. So the probability that M2 is chosen as a student with no experience is \frac{9}{14}.

For the third member, there are 13 students, of which 8 have no experience. So the probability that M3 is chosen as a student with no experience is \frac{8}{13}.

For the last member, there are 12 students, of which 7 have no experience. So the probability that M4 is chosen as a student with no experience is \frac{7}{12}.

What is the probability that none of the members chosen for the team have any competition experience?

This is

P = \frac{10}{15}*\frac{9}{14}*\frac{8}{13}*\frac{7}{12} = 0.1538

The correct answer is:

A) 0.1538

7 0
3 years ago
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