Answer: Choice C. mean > median
================================================
Explanation:
Multiply each measure with their corresponding frequency.
- 8*1 = 8
- 10*3 = 30
- 14*2 = 28
Add up those products: 8+30+28 = 66
Then divide by the total frequency n = 1+3+2 = 6 to get 66/6 = 11 as the mean.
mean = 11
----------------
Since we have n = 6 values in this list, this means the median is between slot n/2 = 6/2 = 3 and slot 4.
Note how that places us in the middle row because 1+3 = 4 encapsulates both of those slots mentioned. So the median is 10.
Or you could list out the values in roster notation {8, 10, 10, 10, 14, 14} to see that {10,10} occupy the middle most slots. So the median is (10+10)/2 = 20/2 = 10.
median = 10
-----------------
The mode is simply the most frequent value. The table shows that mode = 10 since it occurs 3 times, compared to 8 showing up 1 time and 14 showing up twice.
-----------------
We have the following summary
- mean = 11
- median = 10
- mode = 10
With that in mind, let's go through the answer choices.
- We can see that mean < mode is false, since it should be mean > median, so cross choice A off the list.
- mean = median is also false, so choice B is crossed off as well.
- mean > median is true since 11 > 10 is true. Choice C is the answer. Note how this being true directly contradicts choice B, which is another reason to see why choice B is false.
- median > mode is false because 10 > 10 is false. It should be median = mode. Choice D is crossed off the list.
Answer:
8/7
Step-by-step explanation:
The Numerator is bigger than the denominator which in turn can be converted to a mixed fraction.
Answer:
Since they are 11 spaces for bicylces and the playground has as many spaces for bicycles then we use this equation 3 x 11 = 33 to find the total number of bicycles spaces on the rack by the playground.
Answer:
n=65th term
Step-by-step explanation:
AP:3,15,27,39......
From the AP
a=3
a+d=15
a+2d=27
3+d=15 (1)
3+2d=27 (2)
Subtract (1) from (2)
We have,
2d-d=27-15
d=12
54th term=a+(n-1)d
=3+(54-1)12
=3+(53)12
=3+636
=639
The term is 132 more than the 54th term
132+54th term
=132+639
=771
Find the term
771=a+(n-1)d
771=3+(n-1)12
771-3=12n-12
768=12n-12
768+12=12n
780=12n
n=780/12
=65
n=12
The term which is 132 more than the 54th term is the 65th term
