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artcher [175]
3 years ago
13

War Eagle spied 1428 antelope and wildebeests grazing on the savannah. If the ratio of antelope to wildebeests was 9 to 5, how m

any antelope were there? (Answer is 918 but idk how to solve it.....)
Mathematics
1 answer:
Nonamiya [84]3 years ago
4 0

Answer:

9:5 = 1428:x

ratios can also be written as fractions, so

9/5 = 1428/x

solve for x

9/5 × x = 1428

x = 1428 / (9/5)

x = 918

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You have one type of nut that sells for $4.50/lb and another type of nut that sells for $8.00/lb. You would like to have 28 lbs
-Dominant- [34]

Answer:

I will need 26.4 pounds of the expensive nuts and 1.6 pounds of the cheap nuts.

Step-by-step explanation:

Since I have one type of nut that sells for $ 4.50 / lb and another type of nut that sells for $ 8.00 / lb, and I would like to have 28 lbs of a nut mixture that sells for $ 7.80 / lb, to determine how much of each nut will I need to obtain the desired mixture, the following calculation must be performed:

8 x 0.95 + 4.5 x 0.05 = 7.825

8 x 0.94 + 4.5 x 0.06 = 7.79

0.94 x 28 = 26.32

26.4 x 8 + 1.6 x 4.5 = 218.4

218.4 / 28 = 7.8

Thus, I will need 26.4 pounds of the expensive nuts and 1.6 pounds of the cheap nuts.

7 0
3 years ago
In a school, 2/3 of the students study a language.
Nimfa-mama [501]

Answer:

6:15

Step-by-step explanation:

2/3= 10/15

2/5= 6/15 study french

6:15

6 0
3 years ago
The amount of trout y (in tons) caught in a lake from 1995 to 2014 can be modeled by the equation y = -0.08x2 + 1.6x + 10, where
Lapatulllka [165]
For this case, the first thing we want to do is substitute the value of y = 15 in the equation.
 We have then:
 15 = -0.08x ^ 2 + 1.6x + 10
 Rewriting we have:
 0 = -0.08x ^ 2 + 1.6x + 10 - 15
 0 = -0.08x ^ 2 + 1.6x - 5
 The solutions are:
 x1 = 3.876275643042054
 x2 = 16.123724356957947
 Nearest whole number:
 x1 = 4
 x2 = 16
 were about 15 tons of trout caught in the lake in the years:
 1995 + 4 = 1999
 1995 + 16 = 2011
 Answer:
 The year 1999 and the year 2011
3 0
3 years ago
Histogram or Bar Chart? Select which graphical display is most appropriate to describe the distribution for each of the variable
lara31 [8.8K]

Answer:

a) Bar chart

b) Histogram

c) Bar chart

d) Histogram

Step-by-step explanation:

a) Trash pick-up DAY for each HOUSEHOLD in Ames - This is categorical data because, we are talking about days of the week. For instance, Household 1 might have Sunday as Trash pick-up day and that could be accumulated into frequency. Hence, BAR chart is the most appropriate.

b) Patient WAIT-TIME at ISU. This is continuous (quantitative) data. And the most appropriate is HISTOGRAM.

c) Number of trips taken during a GIVEN SCHOOL YEAR by EACH ISU STUDENT. Let say we have 5 ISU STUDENTS. Student 1 had 5 trips, student 2 had 10 trips, etc.

We want to see which student has the most and least trip in that particular school year. Although is count data but the most appropriate graphical display is BAR chart.

d) TAX BRACKET of ALL Iowa RESIDENTS. This is a continuous (quantitative) data. The most appropriate graphical display is HISTOGRAM.

5 0
3 years ago
-4 > x - 3 find x in the equation
dimulka [17.4K]

Answer:

X= -1

Step-by-step explanation:

8 0
3 years ago
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