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emmasim [6.3K]
3 years ago
10

Estimate 59 times 8 A. 60 B. 480 C. 700 D. 240

Mathematics
2 answers:
Lana71 [14]3 years ago
8 0

Answer:

480 is the answer

Step-by-step explanation:

Leviafan [203]3 years ago
7 0

Answer:

b 480

Step-by-step explanation:

59 times 8 is 472 just estamate

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What is the distributive property of 4+10
IgorC [24]

Answer:

  2(2 +5)

Step-by-step explanation:

We presume you want to rewrite the expression making use of the distributive property. For that, it is helpful to find a factor common to the two terms. The GCD of 4 and 10 is 2, so we can factor that out:

  4 + 10 = 2(2 +5)

_____

Of course, you can use any factor you like. It doesn't need to be an integer.

  = (1/3)(12 +30)

  = 0.4(10 +25)

  = 4(1 +2.5)

4 0
3 years ago
Help!!!!!!! Meeee plead I’ve already out this question down but nobody answers it:(
lorasvet [3.4K]

Answer:

1. Y = 6

2. Y = 8

3. Y = 1

4. Y = 3

Step-by-step explanation:

1. Y = -(-1) + 5 = 1 + 5 = 6

2. Y = -(-3) + 5 = 3 + 5 = 8

3. Y = -4 + 5 = 1

4. Y = -2 + 5 = 3

Hope this helps you!

3 0
3 years ago
Read 2 more answers
A filling machine puts an average of four ounces of coffee in jars, with a standard deviation of 0.25 ounces. forty jars filled
Lunna [17]
Let's attack this problem using the z-score concept.  The sample std. dev. here is (0.25 oz)/sqrt(40), or 0.040.  Thus, the z score representing 3.9 oz. is
        3.9 - 4.0
z = -------------- = -2.5
          0.040 

In one way or another we must find the area under the std. normal curve that lies to the left of z = -2.5.  Use a table of z-scores or a calculator with built-in statistics functions.  According to my TI-83 Plus calculator, that area is

0.006.  One way of interpreting this that with so small a standard deviation, most volumes of coffee put into the jars are very close to the mean, 4 oz.
4 0
4 years ago
(16 - 6) + f - 9 = 12
CaHeK987 [17]

Answer:

f = 11

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Someone help with this
elena-14-01-66 [18.8K]

The quadrants are I, II, III, and IV, (meaning 1, 2, 3, and 4). The first quadrant is in the upper right, which has both positive x and positive y values. The second quadrant is the upper left, which has negative x and positive y values. The third quadrant is the lower left, which has both negative x and y values. The fourth quadrant is the lower right, which has positive x and negative y values. Using this knowledge and our positive and negative signs, the following are the answers to questions 1-6.

1) (-4, -2) - Quadrant III, both x and y are negative

2) (0, -7) - This point is actually on the y-axis. The x value is 0 and the y value is -7, so the graph is 7 units down from the origin on the y-axis.

3) (0,0) - This point is the origin, or where the x and y axes cross (the middle of the graph).

4) (6, -9) - This point is in Quadrant IV, because it has a positive x value and a negative y value

5) (3,5) - This point is in Quadrant I, because both the x and y values are positive.

6) (8,0) - This point is on the x-axis. The y-value is zero, so this point is 8 units to the right of the origin between Quadrant I and Quadrant IV.

Using the knowledge presented above, to graph the points given to you in the second part of the problem, first you can figure out what quadrant or part of the graph the point is on. Then, you can count the number of units (squares on the graph) in the right direction (remember that up is positive on the y-axis and down is negative, and to the right is positive on the x-axis and to the left is negative) in order to plot the points. Then, you must connect the points that correspond to the same figure in order to create the figures.

Please comment if you have any questions!

Hope this helps!

7 0
4 years ago
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