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Vera_Pavlovna [14]
3 years ago
15

Choose the value to make the equation true.

Mathematics
2 answers:
mart [117]3 years ago
6 0

Step-by-step explanation:

= 7 . 09

Ludmilka [50]3 years ago
6 0
7.09 divided by 1 equals 7.09
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Choose the rule to describe the transformation:
butalik [34]
<h3><u>We are given:</u></h3>

The initial points:             T(2 , 3)      U(5, 4)       V(2, 0)

The transformed points: T'(-1, 2)       U'(2,3)          V'(-1, -1)

<h3><u>Identifying the Transformation rule:</u></h3>

Since all these points will follow the same rule, we will take a pair of initial and transformed points and compare them

T(2, 3) → T'(-1, 2)

We can see that these points are not reflected across the y-axis

<u>Checking if they have a dilation of 0.25 about the origin:</u>

Dilation of 0.25 about the origin basically means if the Initial x and y coordinates are multiplied by 0.25 to form the transformed points

So, if the points have a dilation of 0.25:

x (initial) * 0.25 = x(final)

2*0.25 = -1

0.5 ≠ -1

Hence, there is no dilution of 0.25

<u>Checking if the given points are translated:</u>

To check this, we will take 2 pairs of initial and transformed points

T(2,3) →  T'(-1,2)

U(5,4) → U'(2,3)

To check if there is transformation, we need to check if the difference between the x and y coordinates of initial and transformed points is equal

<u>Change in coordinates of T:</u>

x-coordinates:

x(final) - x(initial) = x(change)

x(change) = -1 - (2)

x(change) = -3

y-coordinates:

y(change) = y(final) - y(initial)

y(change) = 2 - (3)

y(change) = -1

<u>Change in coordinates of U:</u>

x-coordinates:

x(change) = x(final) - x(initial)

x(change) = 2 - 5

x(change) = -3

y-coordinates:

y(change) = y(final) - y(initial)

y(change) = 3 - 4

y(change) = -1

Since there is the same change in x and y coordinates of the initial and transformed points, we know that Translation took place

Since the change in x is -3 and the change in y is -1, the translation will look like:

(x-3 , y-1)

Which is also option d.

Hence, option d is the correct answer

3 0
3 years ago
A house is valued at $118,000.00. The homeowner decides to add on a two-car garage that increased the value of the home by 15%.H
nasty-shy [4]

Answer:

The value of the house after adding the garage is $135,700.

Step-by-step explanation:

Given,

value of house before adding garage = $118,200.00

we need to find the value of house after adding two car garage.

Solution,

Since after adding two car garage the value of the house increased by 15%.

So firstly we will find out the 15% of the value of the house after adding garage.

So we can say that;

15% of the value of the house after adding garage is equal to 15 divided by 100 the multiplied with the value of the house before adding garage.

15% of the value of the house after adding garage = \frac{15}{100}\times118,000=\$17,700

Now, The value of the house after adding garage is equal to the sum of value of house before adding garage and 15% of value of house before adding garage.

We can frame it in equation form as;

The value of the house after adding garage = \$118,000+\$17,000=\$135,700

Hence The value of the house after adding the garage is $135,700.

3 0
3 years ago
Please help the picture is
asambeis [7]

The walls are vertical so the angle opposite X would be a right angle which is 90 degrees.

X would be 180 - 90 - 35 = 55 degrees

X and 2y - 5 are complementary angles which add together to equal 90:

2y - 5 + 55 = 90

Simplify:

2y +50 = 90

Subtract 50 from both sides:

2y = 40

Divide both sides by 2:

y = 20

7 0
3 years ago
Read 2 more answers
roger bought 8 small bricks for his garden for $5.46. the total weight of the bricks was 6 1/4 pounds how many pounds does one b
mestny [16]

Answer:

0.78125 pounds

Step-by-step explanation:

the weight of 8 brick is 6.25 pound

divide the weight by 8 to take the weight for the one brick

3 0
3 years ago
Can someone solve this question PLEASE?? check the attached pic
Talja [164]

Answer:

someone ur so ugly

Step-by-step explanation:

5 0
2 years ago
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