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4 years ago

How many solutions does these equations have? One, infinite or no solutions?

Mathematics

1 answer:

s2008m [1.1K]4 years ago

5 0

Answer:

1. 7(y + 3) = 5y+8: one solution

2. 10 + 6x= 2(5+3x): infinite solutions

3. 3x + 5 - x=2x + 7: no solutions

4. 4x - 4 = 2x + 8: one solution.

Explanation:

1. 7(y+3)=5y+8

a) Distributive property of multiplication over addtion:

7y + 21 = 5y + 8

b) Subtraction property of equalities:

7y - 5y = 8 - 21

c) Combine like terms:

2y = - 13

d) Division property of division:

y = - 13/2

e) Conclusion: the equation has one solution.

2. 10 + 6x = 2(5+3x)

a) Distributive property of multiplication over addition:

10 + 6x = 10 + 6x

b) Subtraction property of equality:

6x - 6x = 10 - 10

c) Simplify (combine like terms)

0 = 0

That is an identity, i.e. that is always true, no matter the value of x.

d) Conclusion: the equation has infinite solutions.

3. 3x + 5 - x = 2x + 7

a) Combine like terms:

2x + 5 = 2x + 7

b) Subtraction property of equalities:

2x - 2x = 7 - 5

c) Combine like terms (simplify)

0 = 2

That is always false, no matter the values of x.

d) Conclusion: the equation does not have any solutions.

4. 4x - 4 = 2x + 8

a) Subtraction property of equality

4x - 2x - 4 = 2x - 2x + 8

b) Combine like terms

2x - 4 = 8

c) Addtiion property of equalities:

2x = 8 + 4

d) Combine like terms (simplify)

2x = 12

e) Division property of equalities:

x = 6

f) Conclusion: the equation has one solution

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