Answer:
The information we need is that the angle between the sides (that is, angle TVU for triangle TVU and angle WVX for triangle WVX) need to be equal.
These angles are vertically opposite angles, because they are formed by two lines crossing, so these angles are equal.
Step-by-step explanation:
The SAS Congruence Theorem says that if two triangles have 2 equal sides and the angle between these sides are also equal, the triangles are congruent.
In this question, we know that the sides UV and VW are congruent, as V is the midpoint of UW. We also know that TV = VX, so now we have two equal sides for each triangle.
The information we need is that the angle between the sides (that is, angle TVU for triangle TVU and angle WVX for triangle WVX) need to be equal.
These angles are vertically opposite angles, because they are formed by two lines crossing, so these angles are equal.
Now we can conclude that the triangles are congruent.
Answer: If the left side and the right side of the equation are equal, the equations has infinitely many solutions.
Step-by-step explanation:
The options are not clear, so I will give you a general explanation of the procedure you can use to solve this exercise.
The Slope-Intercept form of the equation of a line is the following:
Where "m" is the slope and "b" is the y-intercept.
For this exercise you need to remember that, given a System of Linear equations, if they are exactly the same line, then the System of equations has Infinitely many solutions.
If you have the following system:
You can simplify the second one:
Then, both equations are the same line.
By definition you can also write the systemf making both equations equal to each other:
So, if the left side and the right side are equal, the equations has infinitely many solutions.
Answer:
A. 2612
cause 2612 is a even number
Answers
8/45
is already in the simplest form. It can be written as 0.177778 in decimal form (rounded to 6 decimal places).
Step-by-step explanation:
A, the interquartile range is 10, does not fit.
The interquartile range is found by subtracting the upper quartile and the lower quartile; in a box-and-whisker plot these are the outer edges of the box. In this case, they are 40 and 20; 40-20 = 20, not 10.
