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2 years ago

A dozen donuts cost $2.99. To the nearest cent, what is the cost of 1 donut?

Mathematics

2 answers:

kozerog [31]2 years ago

4 0

Answer

25 cents

Step-by-step explanation:

Marianna [84]2 years ago

4 0

Answer:

that person is correct, each donut is only .25 cents because every 4 donuts are $1, multiply 4 by 3 and you get 12, 12=dozen. Since the total price is $3 it makes sense that each donut in .25 cents and every 4 donuts $1

HOPE THIS HELPS AND HOPE THIS MAKES SENSE!!!!!!!

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what algebraic expression must be added to the sum of 3x squared + 4x + 8 and 2x squared -6x + 3 to give 9x squared -2x - 5 as t

gregori [183]

3x^2 + 4x + 8 + 2x^2 - 6x + 3 to give result as 9x^2 -2x - 5

3x^2 + 4x + 8 + 2x^2 - 6x + 3
= 5x^2 - 2x + 11

so

9x^2 -2x - 5 - (5x^2 - 2x + 11)
= 9x^2 -2x - 5 - 5x^2 + 2x - 11
= 4x^2 -16

answer

expression (4x^2 -16) must be added to the sum of (3x^2 + 4x + 8) and (2x^2 - 6x + 3) to give the result as (9x^2 - 2x - 5)

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3 years ago

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3 years ago

Solve linear equations Solve for x -2(4x + 3) = 3(x + 1)

inna [77]

Answer:

x = - $\frac{9}{11}$

Step-by-step explanation:

Given

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3 years ago

Read 2 more answers

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-Dominant- [34]

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3 years ago

Select the two values of x that are roots of this equation. 2x^2+ 1 = 5x

iren [92.7K]

Answer:

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

Step-by-step explanation:

One is asked to find the root of the following equation:

$2x^2+1=5x$

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

$ax^2+bx+c=0$

Change the given equation using inverse operations,

$2x^2+1=5x$

$2x^2-5x+1=0$

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$

Simplify,

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$

$\frac{5(+-)\sqrt{25-8}}{4}$

$\frac{5(+-)\sqrt{17}}{4}$

Rewrite,

$\frac{5(+-)\sqrt{17}}{4}$

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

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3 years ago