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Natali5045456 [20]
3 years ago
11

Hello can anyone help me plz its math

Mathematics
1 answer:
AlladinOne [14]3 years ago
3 0
The answer would be 4/9 hope it helped(:
You might be interested in
Someone help me plzz
galina1969 [7]
Answer: y=5x+3
Step by step explanation:
Perpendicular meaning that the product of the slope/gradient is -1 hence ...
-1/5 * x = -1
x = -1/-1/5
x = 5
The equation perpendicular to y=-1/5x-3 is y=5x-c
Now it contains the points (1,2)
x variable is 1 and y variable is 2 plug them into the line equation
2=5(1)-c
2=5-c
2-5=-c
-3=-c divide by -1
3=c
Hence the perpendicular equation is y=5x+3
Hopefully it’s correct :)
5 0
3 years ago
What is the approximate volume of a cylinder with a diameter of 10 meters and a height of 5 meters? Use 3.14 for pi. A. 392.5 m3
EastWind [94]
For cylinder
d=10m
So r=5m
h=5m
volume=pi×r^2×h
=3.14×5×5×5
=3.14×125
=392.5m^3
So option a is correct.
3 0
3 years ago
Read 2 more answers
Help ASAP please!!!!!!!
Bumek [7]
I think the answer will be (-4,3)
4 0
3 years ago
Suppose that a sample mean is .29 with a lower bound of a confidence interval of .24. What is the upper bound of the confidence
Ganezh [65]

Answer:

The upper bound of the confidence interval is 0.34

Step-by-step explanation:

Here in this question, we want to calculate the upper bound of the confidence interval.

We start by calculating the margin of error.

Mathematically, the margin of error = 0.29 -0.24 = 0.05

So to get the upper bound of the confidence interval, we simply add this margin of error to the mean

That would be 0.05 + 0.29 = 0.34

3 0
3 years ago
Solve x2-14x+21=0 by completing the square
ankoles [38]
x^2-14x+21=0\\\\x^2-2x\cdot7+7^2-7^2+21=0\\\\(x-7)^2-49+21=0\\\\(x-7)^2-28=0\\\\(x-7)^2=28\iff x-7=-\sqrt{28}\ \vee\ x-7=\sqrt{28}\\\\x=7-\sqrt{4\cdot7}\ \vee\ x=7+\sqrt{4\cdot7}\\\\x=7-2\sqrt7\ \vee\ x=7+2\sqrt7
4 0
3 years ago
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