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2 years ago

9

Sharon went to the mall and purchased 4 pairs of jeans for $24.99 each, 1 pair of gym shoes for $125.57 and lunch for 15.93 the

tax on all of the items that she purchased was 6%. How much did she spend at the mall?

1 answer:

alekssr [168]2 years ago

4 0

Answer:

$226.97

Step-by-step explanation:

$24.99 x 4 = $99.96

$99.96 + $125.57 = $225.53

$225.53 + $15.93 = $241.46

$241.46 - 6% = $226.97

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Which expression is the simplest form of 3(2x + y) + 4(x - 4y) + x2?

g100num [7]

Answer:

x^2 + 10x - 13y.

Step-by-step explanation:

3(2x + y) + 4(x - 4y) + x^2 First apply the Distributive law to the parentheses:

= 6x + 3y + 4x - 16y + x^2 Now add like terms:

= 10x - 13y + x^2.

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2 years ago

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One soda and one taco costs $2.1. Two sodas and three tacos cost $5.15. Find the cost of a soda and a taco. Whoever answer this

DaniilM [7]

Answer:

Soda costs $1.15 and taco costs $0.95.

Step-by-step explanation:

x + y = 2.1

2x + 3y = 5.15

Multiply the first equation by -2 to eliminate x

-2x - 2y = -4.2

2x + 3y = 5.15

Add

y = 0.95

Find x with the original first equation

x + y = 2.1

x + 0.95 = 2.1

x = 2.1 - 0.95

x = 1.15

hope it helps :)

5 0

2 years ago

Ven Diagrams with union and intersection problems shading in diagram

Anika [276]

Answer:

4 types of questions one will be to read, 2nd will be to subtract, one will be to add, the next will be to find missing numbers each are expressed below.

Step-by-step explanation:

This is a two-circle Venn diagram. The 1st circle is A, and the 2nd circle is B. The complete Venn diagram represents the union of A and B, or A ∪ B.

Just intersect is A ∩ B

Just intersect B ∩ A

A∩B= A∩B={2} differs significantly from below.

A small ∁

(sometimes denoted as ~A or ¬A)

is pronounced as: "A complement" (or "not A", for the other notations)

means: the new set gets everything that is in the universe but is outside of A; it's okay if the element is in B, just so long as it is not also in A

in terms of the elements: {1, 2, 3, 4} – {1, 2}

my answer: = A ∁ ={3,4}

A – B (or A \ B)in terms of the elements: {1, 2} – {2, 3}

A – B = {1}

A∪B)=¬(A∪B)in terms of the elements: = {1, 2, 3, 4} – {2}

in terms of the elements: {1, 2, 3, 4} – ({1, 2} ∪ {2, 3}) = {1, 2, 3, 4} – {1, 2, 3}

(4) elements here are just the remainder my answer: my answer:(A∪B)={4}

6 0

2 years ago

How many four-digit whole numbers are there such that the leftmost digit is odd, the second digit is even, and all four digits a

kiruha [24]

Answer: There are 1400 different combinations.

Step-by-step explanation:

The conditions are:

we have 4-digits: abcd.

all the digits are different.

a is an odd number, and b is an even number.

Then, for a, we have the options 1, 3, 5, 7 and 9 (so we have 5 options).

for b, we have the options 0, 2, 4, 6 and 8 (so we have 5 options).

for c, we can have odd or even numbers, so we have 8 options ( remember that there where 2 numbers already taken away, this is why we have only 8 options).

for d we have 7 options (because 3 numbers are already taken).

Then the number of combinations is equal to the product of the number of options for each selection:

C = 5*5*8*7 = 1400

3 0

2 years ago

You want to get from a point A on the straight shore of the beach to a buoy which is 54 meters out in the water from a point B o

anyanavicka [17]

Answer:

$x =\dfrac{45 \sqrt{6}}{ 2}$

Step-by-step explanation:

From the given information:

The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.

Now, let V(x) be the time needed for the runner to reach the buoy;

∴ We can say that,

$\mathtt{V(x) = \dfrac{70-x}{7}+\dfrac{\sqrt{54^2+x^2}}{5}}$

In order to estimate the point along the shore, x meters from B, the runner should stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.

i.e

The differential of V(x) = V'(x) =0

= $\dfrac{d}{dx}\begin {bmatrix} \dfrac{70-x}{7} + \dfrac{\sqrt{54^2+x^2}}{5} \end {bmatrix}= 0$

$-\dfrac{1}{7}+ \dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}=0$

$\dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}$

$\dfrac{5x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}$

$\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{\dfrac{7}{5}}$

$\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{5}{7}$

squaring both sides; we get

$\dfrac{x^2}{54^2+x^2}= \dfrac{5^2}{7^2}$

$\dfrac{x^2}{54^2+x^2}= \dfrac{25}{49}$

By cross multiplying; we get

$49x^2 = 25(54^2+x^2)$

$49x^2 = 25 \times 54^2+ 25x^2$

$49x^2-25x^2 = 25 \times 54^2$

$24x^2 = 25 \times 54^2$

$x^2 = \dfrac{25 \times 54^2}{24}$

$x =\sqrt{ \dfrac{25 \times 54^2}{24}}$

$x =\dfrac{5 \times 54}{\sqrt{24}}$

$x =\dfrac{270}{\sqrt{4 \times 6}}$

$x =\dfrac{45 \times 6}{ 2 \sqrt{ 6}}$

$x =\dfrac{45 \sqrt{6}}{ 2}$

8 0

2 years ago