Answer:
P(x)= x ^4-3x^3+x^2-4
Step-by-step explanation:
Given data
R(x) = 2x ^4-3x^3+2x-1
c(x)=x^4-x^2+2x+3
We know that
P(x)=R(x)-C(x)
Hence
P(x)= 2x ^4-3x^3+2x-1-(x^4-x^2+2x+3)
open bracket
P(x)= 2x ^4-3x^3+2x-1-x^4+x^2-2x-3
Collect like terms
P(x)= 2x ^4-x^4-3x^3+x^2-2x+2x-3-1
P(x)= x ^4-3x^3+x^2-4
I think it’s B but I’m not 100%
Base on the function that you give and the data that are given. The point on the curve at which the tangent lines pass through the point (1,1). Base on my calculation and through my analyzations i came up with an answer of <span>-2x+3 = x+3/x</span>
Answer:
1st= 2 1/2
2nd= ???
3rd= 1/3
4th= 1/7
5th= 5/144
Step-by-step explanation:
Step-by-step explanation:
x=20
y=100
solution in image