3x+y=0 and x+2y=7
i)
a= intercept on x axis
b= intercept on y axis
from the question
a=2b
x/2b+ y/b=1
x+2y=2b
since it passes through the point (3,2)
then 3+4=2b
7/2=b
x+2y=7 putting the value of b
ii) given b =3a
then x/a+ y/ 3a =1
3x+y=3a
it passes through ( -1,3) then
-3+3=3a
a=0
3x+y=0
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I can’t answer this with out the distance they jumped.
$4.25 + $1.50 = $5.75= 2 miles
10 x $1.50 = $15.00=10 miles
10 + 2 = 12 miles
$5.75 + $15.00 = $20.75
P(A|B)<span>P(A intersect B) = 0.2 = P( B intersect A)
</span>A) P(A intersect B) = <span>P(A|B)*P(B)
Replacing the known vallues:
0.2=</span><span>P(A|B)*0.5
Solving for </span><span>P(A|B):
0.2/0.5=</span><span>P(A|B)*0.5/0.5
0.4=</span><span>P(A|B)
</span><span>P(A|B)=0.4
</span>
B) P(B intersect A) = P(B|A)*P(A)
Replacing the known vallues:
0.2=P(B|A)*0.6
Solving for P(B|A):
0.2/0.6=P(B|A)*0.6/0.6
2/6=P(B|A)
1/3=P(B|A)
P(B|A)=1/3