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Tamiku [17]
3 years ago
10

A school has a capacity of 965 students. If 541 students are already enrolled in the school, how many students remain? Round to

the nearest ten.
Mathematics
2 answers:
kifflom [539]3 years ago
8 0

Answer:

420 students

Step-by-step explanation:

965-541=424

round to the nearest ten and you get 420

i hope this helped, please mark this as brainliest! thanks

Alex777 [14]3 years ago
3 0

Answer:

The answer is 420

Step-by-step explanation:

You first do the equation 965 - 541. The answer to that is 424, but when you round it to the nearest ten, the answer would be 420.

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The scale of a map is 1/8 inch = 10 miles. If 2 cities are 3 inches apart on the map, he
ch4aika [34]

Answer:

They are 240 miles away from each other

8 0
2 years ago
Let ​ f(x)=x2+6x−16 ​. Enter the x-intercepts of the quadratic function in the boxes. and
gizmo_the_mogwai [7]

Answer:

x = - 8, x = 2

Step-by-step explanation:

Given

f(x) = x² + 6x - 16

To find the x- intercepts equate f(x) to zero, that is

x² + 6x - 16 = 0 ← in standard form

(x + 8)(x - 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 8 = 0 ⇒ x = - 8

x - 2 = 0 ⇒ x = 2

8 0
3 years ago
Helpppppppppppp!!!!!!!!!
OverLord2011 [107]

Answer: D

Step-by-step explanation:

Try to draw the X and Y axis: When you shift the function to left it translates as going to the left of the X axis. So what you want is that every value of X on the parent function to correspond to the same x value minus four.

You can apply the same logic to get the + 6

3 0
3 years ago
The gcf of two numbers less than or equal to 12 is 2. Their LCM is 20.What are the numbers?
bixtya [17]

We know:

LCM(a,\ b)=\dfrac{ab}{GCF(a,\ b)}

We have

GCF(a,\ b)=2,\ LCM(a,\ b)=20,\ a\leq12,\ b\leq12

Substitute:

20=\dfrac{ab}{2}\qquad|\cdot2\\\\ab=40

40=1\cdot40=2\cdot20=4\cdot10=5\cdot8

Only 4 and 10 meet the requirements of the question.

--------------------------------------------------------------------

40 and 1 NOT, because 40 > 12

20 and 2 NOT, because 20 > 12

5 and 8 NOT because GCF(5, 8) = 1

5 0
3 years ago
PLEASE PLEASE PLEASEE PLEASEEEEESE HELPME!?!?!? IM SO BAD AT MATH PLEASE HELP!!!
Fiesta28 [93]
For this case we have the following function:
 f (x) = 0.01 * (2) ^ x

 By definition, the average rate of change is given by:
 AVR =  \frac{f(x2) - f(x1)}{x2 - x1}
 We evaluate the function for the given values:
 For x = 7:
 f (7) = 0.01 * (2) ^ 7

f (7) = 1.28
 For x = 14:
 f (14) = 0.01 * (2) ^ {14}  f (14) = 163.84
 Then, replacing values we have:
 AVR = \frac{163.84 - 1.28}{14 - 7}
 AVR = 23.22
 Answer:
 
the average rate of change from x = 7 to x = 14 is:
 
a. 23.22 
7 0
3 years ago
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