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iogann1982 [59]
3 years ago
10

Help solve equations by completing the square

Mathematics
1 answer:
Allushta [10]3 years ago
5 0

x^2+10x+22=13\\x^2+10x+22-13=0\\x^2+10x+9=0\\

Now completing the square.

(x^2+10x)+9=0\\(x^2+10x+25)+9-25=0\\(x+5)^2-16=0\\(x+5)^2=16

(x+5)² = 16 is the rewritten equation... For first question btw.

For the solutions to the equation -

x+5=\sqrt{16},-\sqrt{16} \\x+5=4,-4\\x=4-5,-4-5\\x=-1,-9

x = -1,-9 is the solution, for the second question.

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A circuit has a current of 1.2 a. if the voltage decreases to one-third of its original amount while the resistance remains cons
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Given that the resistance remains constant, if the voltage decreases to one-third of its original amount, the resulting current in the circuit is 0.4A

<h3>What is Ohm's Law?</h3>

Ohm’s law states that the potential difference between two points is directly proportional to the current flowing through the resistance.

It is expressed as;

V = IR

Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.

Given that;

Initially, A circuit has a current I = 1.2A

V = IR

R = V/I

R = V/1.2A ...... let this be equation 1

Next, voltage decreases to one-third of its original amount while the resistance remains constant.

Meaning Voltage = 1/3 of V = V/3

Hence;

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From equation 1 ( R = V/1.2A )

V/3 = I × V/1.2A

V/3 = IV/1.2A

We cross multiply

V1.2A = 3IV

I = V1.2A / 3V

I = 1.2A / 3

I = 0.4A

Therefore, given that the resistance remains constant, if the voltage decreases to one-third of its original amount, the resulting current in the circuit is 0.4A

Learn more about potential difference here: brainly.com/question/2364325

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Step-by-step explanation:

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