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3 years ago

Oranges cost $3.60 per dozen how much does 1 cost?

Mathematics

1 answer:

castortr0y [4]3 years ago

6 0

If 6 oranges cost 3.60 than one orange costs .60. To find, divide total price by number of oranges.

3.60/6 = .60

There is no set of pound in a gallon because we do not know the substance. Different liquids weigh different amounts.

3.5 gallons is equal to 448 ounces. To find, multiply the number of gallons (3.5) by the amount of ounces in a gallon (128)

3.5 * 128 = 448

Pound and pints are like gallons and pound. Unless we know the substance we cannot solve.

.75 pints is equal to 12 ounces. To find that, we multiply the number of pints (.75) by the number of ounces in a pint (16)

.75 * 16 = 12

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coach cliffman made a deposit of $1,800 into an account that earns 2% annual simple interest. find the amount of interest that c

igomit [66]

He earns $36 after 3 years

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2 years ago

What is the reciprocal

weqwewe [10]

Answer is C. 7/12 has the reciprocal of 12/7. When You multiply by a reciprocal, you just switch the numerator and denominator. The answer does NOT become negative. It would change the fraction itself.
Example:
3/6= 6/3
5/7= 7/5

3 0

3 years ago

Read 2 more answers

Consider f and c below. f(x, y, z) = (y2z + 2xz2)i + 2xyzj + (xy2 + 2x2z)k,

qaws [65]

$\dfrac{\partial f}{\partial x}=y^2z+2xz^2$
$f(x,y,z)=xy^2z+x^2z^2+g(y,z)$

$\dfrac{\partial f}{\partial y}=2xyz+\dfrac{\partial g}{\partial y}=2xyz$
$\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)$

$\dfrac{\partial f}{\partial z}=xy^2+2x^2z+\dfrac{\mathrm dh}{\mathrm dz}=xy^2+2x^2z$
$\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=0$

$\implies f(x,y,z)=xy^2z+x^2z^2+C$

8 0

3 years ago

Solve asap! this is for a grade -14 + x + 6 = -14

tino4ka555 [31]

Answer:

= −6

Step-by-step explanation:

6 0

2 years ago

Y varies directly as x. Y=42 when x=6. Find the value of y when x =15.

pentagon [3]

Answer:

y=120

Step-by-step explanation:

Y varies directly as x is written as

$y \alpha x$

introducing a constant

y=kx

from the question, when y=48, x=6

substitute it in the formula

48=6k

making k the subject by dividing through by 6

$\frac{48}{6} = \frac{6k}{6}$

k=48/6

k=8

put the value of k in the expression y=kx

y=8x

from the question,the value of y when x=15 is given by

y=8×15

y=120.

4 0

3 years ago