Simplify the following:
(3 + 1/3)/(2 + 2/5)
Put 2 + 2/5 over the common denominator 5. 2 + 2/5 = (5×2)/5 + 2/5:
(3 + 1/3)/((5×2)/5 + 2/5)
5×2 = 10:
(3 + 1/3)/(10/5 + 2/5)
10/5 + 2/5 = (10 + 2)/5:
(3 + 1/3)/((10 + 2)/5)
10 + 2 = 12:
(3 + 1/3)/(12/5)
Put 3 + 1/3 over the common denominator 3. 3 + 1/3 = (3×3)/3 + 1/3:
((3×3)/3 + 1/3)/(12/5)
3×3 = 9:
(9/3 + 1/3)/(12/5)
9/3 + 1/3 = (9 + 1)/3:
((9 + 1)/3)/(12/5)
9 + 1 = 10:
(10/3)/(12/5)
Multiply the numerator by the reciprocal of the denominator, (10/3)/(12/5) = 10/3×5/12:
(10×5)/(3×12)
The gcd of 10 and 12 is 2, so (10×5)/(3×12) = ((2×5) 5)/(3 (2×6)) = 2/2×(5×5)/(3×6) = (5×5)/(3×6):
(5×5)/(3×6)
3×6 = 18:
(5×5)/18
5×5 = 25:
Answer: 25/18
Answer:
Substitute -8 as x into the equation.
h(-8)=-2(-8+5)^2+4
h(-8)=-2(-3)^2+4
h(-8)=-2(9)+4
h(-8)=-18+4
h(-8)=-14
:)
Answer:
Right Triangle, Acute Triangle, and Obtuse Triangle
Step-by-step explanation:
I can't draw it here but the right triangle has a side of 90°.
An acute triangle has a side smaller than 90°.
An obtuse triangle has a side bigger than 90°.
V = (4/3)×3.14×(1.5^3)
V = 14.1 in^3
Answer:
The number of pies does the baker have left is 15.
Step-by-step explanation:
Given : A baker made 20 pies. A Boy Scout troop buys one–fourth of his pies, a preschool teacher buys one–third of his pies, and a caterer buys one–sixth of his pies.
To find : How many pies does the baker have left?
Solution :
Let x be the number of pies does the baker have left.
According to question,
Number of pies buys,
One-fourth =
One-third =
One-sixth =
i.e. 
The number of pies does the baker have left is 15.
