<u><em>Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.</em></u>
Answer:
Any value other than the values
will not be a solution of
.
Step-by-step explanation:
Considering the equation

Steps to solve the equation









As
![\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}](https://tex.z-dn.net/?f=%5Cmathrm%7BFor%5C%3A%7Dx%5E3%3Df%5Cleft%28a%5Cright%29%5Cmathrm%7B%5C%3Athe%5C%3Asolutions%5C%3Aare%5C%3A%7Dx%3D%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%2C%5C%3A%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%5Cfrac%7B-1-%5Csqrt%7B3%7Di%7D%7B2%7D%2C%5C%3A%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%5Cfrac%7B-1%2B%5Csqrt%7B3%7Di%7D%7B2%7D)
![x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B8%7D%7D%2C%5C%3Ax%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B8%7D%7D%5Cfrac%7B-1%2B%5Csqrt%7B3%7Di%7D%7B2%7D%2C%5C%3Ax%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B8%7D%7D%5Cfrac%7B-1-%5Csqrt%7B3%7Di%7D%7B2%7D)
So,

Therefore,
Any value other than the values
will not be a solution of
.
Keywords: solution, value
Learn more about equation solution from brainly.com/question/1679491
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it would be 3 because when you add it, it gets to be 932 and the tens place is 3.
Answer
Find out the how many games did the teams lose .
To prove
Formula

As given
Salem High School's winter sports teams WON 72% of their games last season.
If the teams played 50 games .
Percentage = 72%
Total value = 50
Put in the formula


Number of games win = 36
Number of games teams loses = Total number of games - number of games win
= 50 - 36
= 14
Therefore the number of games team loses are 14 .
The domain of the graph is
while the range of the graph is
.
- The domain of the graph is input values of "x" for which the function exists while the range is the output values "y" for which the function exists.
For the graph, the domain will be the values of the graph along the x-axis.
- Domain =
(Note that -8 is not included)
- For the range, the interval is given as:
. Note that the value of 4 is not included since it is opened.
Learn more on domain and range here: brainly.com/question/1942755
Answer:
Demand theory is an economic principle relating to the relationship between consumer demand for goods and services and their prices in the market. ... As more of a good or service is available, demand drops and so does the equilibrium price.