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3 years ago

Given the sequence 8, 12, 16, 20, 24, what is the sum of the 31st and 19th terms?

Mathematics

1 answer:

erica [24]3 years ago

7 0

Answer:

First term (a) =8

Common difference (d)= t2-t1

=12-8

Now, sum of first 31th term (tn31) =n/2{2a+(n-1)d}

= 31/2{2×8+(31-1)4}

=31/2{16+(30×4)

=31/2(16+120)

=31/2×126

=31×63

Step-by-step explanation:

Similarly use 19 as (n) for the 19th term

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Answer and Step-by-step explanation:

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3 years ago

Read 2 more answers

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Anuta_ua [19.1K]

Answer:

The value of x is 0.5

The value of y is 0.8

The value of z is 0.9

Step-by-step explanation:

* Lets explain how to find the values of x , y and z

- From the attached figure

# $l_{1}$ and $l_{2}$ intersect each other at a point

- When two lines intersect each other at a point they formed

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