Answer:
The answer is cosx cot²x ⇒ the first answer
Step-by-step explanation:
∵ cot²x = cos²x/sin²x
∵ secx = 1/cosx
∴ cot²x secx - cosx = (cos²x/sin²x)(1/cosx) - cosx
= (cosx/sin²x) - cosx
Take cosx as a common factor
∴ cosx[(1/sin²x) - 1] ⇒ use L.C.M
∴ cosx[1-sin²x/sin²x]
∵ 1 - sin²x = cos²x
∴ cosx(cos²x/sin²x) = cosx cot²x
So 20=2 itmes m2 times 5
5m=5 times m
so
5m=20
5 times m=2 times 2 times 5
divid eboth sides y 5
m=2 times 2
m=4
16, 18, 23, 25, 26, 34, 37, 37, 40, 41, 46
37 is the upper quartile value
Answer:

Step-by-step explanation:
Given

Required
Fill in the gaps
Going by the given parameters, we have that

, when factorized is 
Hence; the expression becomes

Combine Fractions

Simplify the denominators

By direct comparison


Hence, the complete expression is

The inequality statement, “An inequality for y greater than or equal to 4” can be written as:
y ≥ 4
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