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Oksana_A [137]
2 years ago
9

Given the sequence 8, 12, 16, 20, 24, what is the sum of the 31st and 19th terms?

Mathematics
1 answer:
erica [24]2 years ago
7 0

Answer:

First term (a) =8

Common difference (d)= t2-t1

=12-8

=4

Now, sum of first 31th term (tn31) =n/2{2a+(n-1)d}

= 31/2{2×8+(31-1)4}

=31/2{16+(30×4)

=31/2(16+120)

=31/2×126

=31×63

Step-by-step explanation:

Similarly use 19 as (n) for the 19th term

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Gnoma [55]

Answer:

C

Step-by-step explanation:

(a)

2 : 4 ( divide both values by 2)

= 1 : 2

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= 1 : 2

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(b)

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= 1 : 3

Thus 1 : 3 = 3 : 9

(c)

4 : 6 ( divide both values by 2 )

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(d)

10 : 2 ( divide both values by 2 )

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Thus 5 : 1 = 10 : 2

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3 years ago
This person did something wrong and I do not know what it is :( Please help this is for points!
Inga [223]

Answer:

It is, indeed, a reduction. But, the scale factor of the dilation should be a fraction instead of a whole number, since the shape has shrunk.

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Hope this helps!

7 0
3 years ago
How do I solve this 9x-(x-24)=2x-(-5+x)
Viefleur [7K]
Combine like terms
8x+24=x+5
subtract x from both sides

8x+24=x+5
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7x+24=5
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divide 7 from both sides
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x= -19/7

7 0
3 years ago
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