2.85 × 10^22. A diamond with a mass of 0.568 g contains
2.85 × 10^22 atoms C.
Diamond is a form of pure carbon.
a) Convert <em>grams of C to moles of C</em>
Moles of C = 0.568 g C × (1 mol C/12.01 g C) = 0.047 29 mol C
b) Convert <em>moles of C to atoms of C
</em>
Atoms of C = 0.047 29 mol C × (6.022 × 10^23 atoms C)/(1 mol C)
= 2.85 × 10^22 atoms C
Answer:
The answer to this question is 33.8
Answer is: the absolute pressure of the air in the balloon is 1.015 atm (102.84 kPa).
n = 0.250 mol; amount of substance.
V = 6.23 L; volume of the balloon.
T = 35°C = 308.15 K; temperature.
R = 0.08206 L·atm/mol·K, universal gas constant.
Ideal gas law: p·V = n·R·T.
p = n·R·T / V.
p = 0.250 mol · 0.08206 L·atm/mol·K · 308.15 K / 6.23 L.
p = 1.015 atm; presure of the air.
Answer: 0.405g
Explanation:
Molar Mass of Be = 9g/mol
Number of mole of Be = 0.045mol
Mass conc. Of Be = 0.045 x 9 = 0.405g
