2 years ago

A sample of silver metal contains 1.91 X 1021 atoms. How many moles of silver is this?

Chemistry

1 answer:

alexandr402 [8]2 years ago

6 0

Answer:

1.91×1021/6.023×10^23

Explanation:

need thanks and make me brainiest if it helps you

You might be interested in

A nucleus with four protons has a total positive charge of _____

vlada-n [284]

this would have a charge of 4 plus

8 0

2 years ago

Create a time that marks important events during the Precambrian Supereon.

Maurinko [17]

I really hope this help!!

8 0

2 years ago

Read 2 more answers

Which species is the conjugate acid of the hemiacetal formed by reaction of benzaldehyde with methanol containing a trace of aci

fiasKO [112]

Answer:

Sulphuric acid is the on

Explanation:

think so

3 0

2 years ago

A chemist must prepare 300.0mL of nitric acid solution with a pH of 0.70 at 25°C. He will do this in three steps: Fill a 300.0mL

d1i1m1o1n [39]

<u>Answer:</u> The volume of concentrated solution required is 9.95 mL

<u>Explanation:</u>

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

pH = 0.70

Putting values in above equation, we get:

$0.70=-\log[H^+]$

$[H^+]=10^{-0.70}=0.199M$

1 mole of nitric acid produces 1 mole of hydrogen ions and 1 mole of nitrate ions.

Molarity of nitric acid = 0.199 M

To calculate the volume of the concentrated solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated nitric acid solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted nitric acid solution

We are given:

$M_1=7.0M\\V_1=?mL\\M_2=0.199M\\V_2=350mL$

Putting values in above equation, we get:

$7.0\times V_1=0.199\times 350.0\\\\V_1=\frac{0.199\times 350}{7.0}=9.95mL$

Hence, the volume of concentrated solution required is 9.95 mL

6 0

2 years ago

Write the complete balanced equation for the following reaction: Al + Fe(NO2)2 Fe + Al(NO2)3

algol13

The equation is already balanced.

7 0

3 years ago