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3 years ago

Where might life exist in the solar system beyond earth

1 answer:

3 0

Some people theorize that there could be life on Mars. The idea came from the fact that Mars and Earth are similar. However Mars' core cooled long ago which means it has no magnetic field which means that its atmosphere is being striped away and surface is bombarded with harmfull radiation from the sun so the prospect of current life is not as good adult could be. Another place is Jupiter's moon Europa. There is evidence indicating that there is a liquid ocean order the icy surface of the moon which which would explain the cracks we see on the surface. Many scientists beleive that this ocean under the surface could harbor life. I hope this helps. Let me know if anything is unclear

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Will mark brainliest!!

olga2289 [7]

Answer:

I think its B im not sure

but i hope this helps

6 0

3 years ago

What’s the temperature of a liquid that turns into a gas at 135 degrees Celsius

nadezda [96]

The answer is about 1/2 it rises very sloe

3 0

3 years ago

When nitrogen gas reacts with hydrogen gas, ammonia gas is formed. how many grams of hydrogen gas are required to react complete

aniked [119]

The balanced equation for the formation of ammonia is as follows
N₂ + 3H₂ ---> 2NH₃
stoichiometry of N₂ to H₂ is 1:3
we need to find the moles of N₂, volume of N₂ has been given
molar volume is where 1 mol of any gas occupies a volume of 22.4 L at STP.
if 22.4 L is occupied by 1 mol
then 3.5 L of gas is occupied by - 3.5 L / 22.4 L/mol = 0.16 mol
number of moles of N₂ present - 0.16 mol
1 mol of N₂ requires 3 mol of H₂
therefore 0.16 mol of N₂ requires - 3 x 0.16 = 0.48 mol of H₂
mass of H₂ required - 0.48 mol x 2 g/mol = 0.96 g
0.96 g of H₂ is required

3 0

4 years ago

PLEASE HELP DUE TODAY 55 POINTS

Dvinal [7]

Answer : The final volume of gas will be, 26.3 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.974 atm

$P_2$ = final pressure of gas = 0.993 atm

$V_1$ = initial volume of gas = 27.5 mL

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $22.0^oC=273+22.0=295K$

$T_2$ = final temperature of gas = $15.0^oC=273+15.0=288K$

Now put all the given values in the above equation, we get:

$\frac{0.974 atm\times 27.5 mL}{295K}=\frac{0.993 atm\times V_2}{288K}$

$V_2=26.3mL$

Therefore, the final volume of gas will be, 26.3 mL

3 0

3 years ago

Read 2 more answers

0.2640 g of sodium oxalate is dissolved in a flask and requires 30.74 mL of potassium

Free_Kalibri [48]

Moles of potassium permanganate = 0.0008

<h3>Further explanation </h3>

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range

Reaction

5Na2C2O4(aq) + 2KMnO4(aq) + 8H2SO4(aq) ---> 2MnSO4(aq) + K2SO4(aq) + 5Na2SO4(aq) + 10CO2(g) + 8H2O(1)

The end point ⇒titrant and analyte moles equal

titrant : potassium permanganate-KMnO4

analyte : sodium oxalate - Na2C2O4

so moles of KMnO4 = moles of Na2C2O4

moles of Na2C2O4(mass = 0.2640 g, MW=134 g/mol) :

$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{0.264}{134 g/mol}\\\\mol=0.002$

From equation, mol ratio Na2C2O4 : KMnO4 = 5 : 2, so mol KMnO4 :

$\tt \dfrac{2}{5}\times 0.002=0.0008$

6 0

3 years ago