F(x)=x^2+2x+1 & g(x)=3(x+1)^2
now, f(x)+g(x)
=x^2+2x+1+3(x+1)^2
=x^2+2x+1+3(x^2+2x+1)
=x^2+2x+1+3x^2+6x+3
=4x^2+8x+4<===answer(c)
next:
f(x)=x^2-1 & g(x)=x+3
now, f(g(x))=(x+3)^ -1
=x^2+6x+9-1
=x^2+6x+8<====answer(b)
i solve two of ur problems.
now try the 3rd one that is similar to no. 1
and try the last two urself.
Answer:
Step-by-step explanation:
find the slope
take a coordinate to fill in
this means that the equation is y=2x-13
and if you add m and b
you get :-11
<u><em>I HOPE THIS HELPS</em></u>
It's not a function because the x value repeated but wasn't accompanied by the same y value . there is (-2,2) and (-2,14) but if they had the same y value like (-2,2) and (-2,2) or (-2,14) and (-2,14) the table would represent a function. If you still dont understand I'll be more than happy to elaborate :)
