Answer:
<em><u>Incomple</u></em><em><u>te</u></em><em><u> </u></em><em><u>ques</u></em><em><u>tion</u></em><em><u>!</u></em>
you have to provide mass to get acceleration
as Newton's 2nd law, force=mass×accln
now,here force toward D is 100N,if it hav mass m
then accln will be 100/m
F - False.
The nucleus of an atom is positively charge.
Answer:
a. The human body has nearly the same density as salt water after exhaling.
b. The human body will always float in the Dead Sea.
Explanation:
According to the concept of floating on the basis of density, any body that is put in a fluid of density greater than its own density will always float due to the force of buoyancy from the liquid.
- The portion of the object submerged while the object is floating depends upon the density of the object as compared to the density of the fluid. This is governed by the equation:
where:
density of the fluid
density of the object
volume of the object submerged in the fluid
total volume of the object
Answer:
Explanation:
First of all, we calculate the resistance of the lamp. The power of the lamp is given by
Where
P = 100 W is the power
V = 250 V is the voltage
R' is the resistance of the lamp
Solving for R',
Now this resistance is connected in parallel to the other resistance R, so their equivalent resistance is
(1)
Now the total power in the circuit is
P = 1100 W
And the voltage is
V = 250 V
So we can write
to find the equivalent resistance:
Therefore, rearranging (1), we find R:
<span>Correct Answer: Option B
The complete question is:
A train starts from rest and accelerates uniformly until it has traveled 3.7 km and acquired a velocity of 30m/s The train then moves at a constant velocity of 30m/s for 410 s. The train then slows down uniformly at 0.065m/s</span>²<span> until it reaches a halt. What distance does the train travel while it is slowing down?
We have the initial velocity u = 30 m/s
Final velocity = v = 0
Acceleration = a = -0.065 m/s</span>²
The negative sign indicates that the train is slowing down.
Using the 3rd equation of motion, we can find the distance covered by the train:
2as = v² - u²
2(-0.065)S = 0 -30²
⇒
S = 6923 meters = 6.9 km