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3 years ago

8. What is the magnitude of the force that is exerted on a 20 kg mass to give it an acceleration of

Physics

1 answer:

Bess [88]3 years ago

6 0

I thought it was F=Ml7 But not sure i haven’t done this in a while

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A 7.0 mm -diameter copper ball is charged to 40 nC. What fraction of its electrons have been removed? The density of copper is 8

mylen [45]

Answer:

$f = 2.6 \times 10^{-13}$

Explanation:

Let the mass of copper ball is "m" gram

now the total number of copper atom present in the ball is given as

$N = \frac{m}{29} \times 6.02 \times 10^{23}$

now the total number of electrons in one copper atom is 29

so total number of electrons in given sample of copper ball is

$N_e = m(6.02 \times 10^{29})$

now diameter of the ball is 7.0 mm

density of the ball = $8900 kg/m^3$

now we have

$m = (\frac{4}{3}\pi r^3)(8900)$

$m = (\frac{4}{3}\pi(\frac{0.007}{2})^3)(8900)$

$m = 1.6 gram$

now we have

$N_e = 9.63 \times 10^{23}$

now the charge on the copper ball is 40 nC

so the number of electrons removed

$Q = ne$

$40 \times 10^{-9} = n(1.6 \times 10^{-19}$

$n = 2.5 \times 10^{11}$

so the fraction of number of electrons removed is given as

$f = \frac{n}{N_e}$

$f = \frac{2.5 \times 10^{11}}{9.63 \times 10^{23}}$

$f = 2.6 \times 10^{-13}$

7 0

3 years ago

The San Andreas Fault in California exists along a _____ plate boundary.

allochka39001 [22]

The answer should be transform

5 0

4 years ago

Ayo, i kinda need help

Elena-2011 [213]

Answer:

I = PRT

18 = 150(R)(2)

18 = 300R

R = 0.06

So A is correct.

Let me know if this helps!

7 0

3 years ago

Read 2 more answers

Explain why energy is needed in active transport.

alexira [117]

Because if not it wouldn't be able to move for example if you don't eat to get the energy you need you would be weak and not be able to move as much and not be able to transport yourself to places :) hope this helps

8 0

4 years ago

A ball is lodged in a hole in the floor near the outside edge of a merry-go-round that is turning at constant speed. Which kinem

dybincka [34]

Answer:

Explanation:

It is given that the ball is lodged in a hole in the floor of merry-go-round that is running at a constant speed.

Now the ball is moving a vertical circular motion

The position of the ball changes w.r.t to the center as it moves in a circular path i.e. vectorially it changes but its magnitude will remain the same.

The velocity of the ball is the same as merry-go-round so its magnitude remains the same but its direction will change continuously.

As the ball is moving in a circular path so a centripetal acceleration will acts towards the center so its value will be continuously changing.

3 0

3 years ago