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asambeis [7]
2 years ago
13

Be sure to answer all parts. Without stratospheric ozone (O3), harmful solar radiation would cause gene alterations. Ozone forms

when the bond in O2 breaks and each O atom reacts with another O2 molecule. It is destroyed by reaction with Cl atoms formed when the C―Cl bond in synthetic chemicals breaks. Find the wavelengths of light that can break the C―Cl bond and the bond in O2. Give your answers in scientific notation. C―Cl × 10 m O2 × 10 m
Physics
1 answer:
Ratling [72]2 years ago
8 0

Answer:

for C-Cl  bond \lambda_1=3.66\times 10^{-9}\ m

for O-O bond \lambda_2=2.43\times 10^{-9}\ m

Explanation:

  • We have the bond enegy for C-Cl, BE_1=327\ kJ.mol^{-1}= 327000\times 1.66\times 10^{-22}\ J\ per\ molecule
  • bond enegy for C-Cl, BE_2=494\ kJ.mol^{-1}= 494000\times 1.66\times 10^{-22}\ J\ per\ molecule

<u>Now as we know the energy of electromagnetic waves is given by:</u>

E=h.\nu

here E = BE

<u>Then for C-Cl:</u>

327000\times 1.66\times 10^{-22}=6.63\times 10^{-34}\times \nu_1

\nu_1=8.18733\times 10^{16}\ Hz

Now wavelength:

\lambda_1=\frac{c}{\nu_1}

\lambda_1=\frac{3\times 10^8}{8.18733\times 10^{16}}

\lambda_1=3.66\times 10^{-9}\ m

<u>For O2:</u>

494000\times 1.66\times 10^{-22}=6.63\times 10^{-34}\times \nu_2

\nu_2=1.236863\times 10^{17}\ Hz

Now wavelength:

\lambda_2=\frac{c}{\nu_2}

\lambda_2=\frac{3\times 10^8}{1.236863\times 10^{17}}

\lambda_2=2.43\times 10^{-9}\ m

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Several springs are connected as illustrated below in (a). Knowing the individual springs stiffness k1 = 20 N/m, k2 = 30 N/m, k3
Hatshy [7]

Answer:

The equivalent stiffness of the string is 8.93 N/m.

Explanation:

Given that,

Spring stiffness is

k_{1}=20\ N/m

k_{2}=30\ N/m

k_{3}=15\ N/m

k_{4}=20\ N/m

k_{5}=35\ N/m

According to figure,

k_{2} and k_{3} is in series

We need to calculate the equivalent

Using formula for series

\dfrac{1}{k}=\dfrac{1}{k_{2}}+\dfrac{1}{k_{3}}

k=\dfrac{k_{2}k_{3}}{k_{2}+k_{3}}

Put the value into the formula

k=\dfrac{30\times15}{30+15}

k=10\ N/m

k and k_{4} is in parallel

We need to calculate the k'

Using formula for parallel

k'=k+k_{4}

Put the value into the formula

k'=10+20

k'=30\ N/m

k_{1},k' and k_{5} is in series

We need to calculate the equivalent stiffness of the spring

Using formula for series

k_{eq}=\dfrac{1}{k_{1}}+\dfrac{1}{k'}+\dfrac{1}{k_{5}}

Put the value into the formula

k_{eq}=\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{35}

k_{eq}=8.93\ N/m

Hence, The equivalent stiffness of the string is 8.93 N/m.

3 0
3 years ago
In a thin film experiment, a wedge of air is used between two glass plates. If the wavelength of the incident light in air is 48
cluponka [151]

Answer:

The thickness is  \Delta y =  2.4 *10^{-6} \  m

Explanation:

From the question we are told that

   The wavelength is  \lambda  = 480 \ nm = 480*10^{-9} \  m

    The first order of the dark  fringe is  m_1 =  16

     The second order of dark fringe considered is  m_2 = 6

Generally the condition for destructive interference is mathematically represented as

        y = \frac{m \lambda}{2}

Here y is the path difference between the central maxima(i.e the origin) and any dark fringe

So  the path difference between the 16th dark fringe and the 6th dark fringe is mathematically represented as

      y_1 - y_2 = \Delta y =  \frac{m_1 \lambda}{2} -  \frac{m_2 \lambda}{2}

=>  y_1 - y_2 = \Delta y =  \frac{16 *480*10^{-9}}{2} -  \frac{6 *480*10^{-9}}{2}

=>  y_1 - y_2 = \Delta y =  5 (480*10^{-9})

=>  \Delta y =  2.4 *10^{-6} \  m

8 0
3 years ago
KIIS FM broadcasts at 102.7 MHz, what is the wavelength of that radio wave?
marysya [2.9K]

Answer:

2.92 m

Explanation:

As we know, frequency × Wavelength = Speed of light

so here frequency of 102.7 MHz can be written as 102.7× 10⁶ Hz..

So Lambda (wavelength) = 3×10⁸/ 102.7 × 10⁶ which gives 2.92 metres or 2.92 × 10¹⁰ Å

3 0
3 years ago
6
Tcecarenko [31]

Explanation:

Melting point

Boiling point

Does the compound

dissolve in water?

Can the compound

conduct electricity?

8 0
3 years ago
1) A plane lands on a runway with a speed of 125 m/s, moving east, and it slows to a stop in 13.0 s. What is the magnitude (in m
valentina_108 [34]

Answer: 1) a = 9.61m/s² pointing to west.

             2) (a) Δv = - 37.9km/s

                  (b) a = - 6.10⁷km/years

Explanation: Aceleration is the change in velocity over change in time.

1) For the plane:

a=\frac{\Delta v}{\Delta t}

a=\frac{125}{13}

a = 9.61m/s²

The plane is moving east, so velocity points in that direction. However, it is stopping at the time of 13s, so acceleration's direction is in the opposite direction. Therefore, acceleration points towards west.

2) Total change of velocity:

\Delta v = v_{f}-v_{i}

\Delta v = -17.1-(+20.8)

\Delta v= -37.9km/s

The interval is in years, so transforming seconds in years:

v = \frac{-37.9}{3.15.10^{-7}}

v=-12.03.10^{7}km/years

Calculating acceleration:

a=\frac{-12.03.10^{-7}}{2.01}

a=-6.10^{7}

Acceleration of an asteroid is a = -6.10⁷km/years .

5 0
2 years ago
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