In this question, we know that mass= 10 kg = 10 x 1000 = 10,000 g
Distance = 1 m and Time = 0.5 s
Power = Force x Velocity
Velocity = Distance / Time = 1 m / 0.5 s = 2 m/s
So, Power = Force x (Distance / Time)
But Force= Mass x Acceleration due to gravity (g)
So, Force = 10 kg x 9.8 m/s
= 98
Therefore, Power =Force x Velocity= 98 x 2 =
196 W
Answer:
hence the relative intensity is 3.0279 ×
Explanation:
Given data
wavelength 755.0 nm = 755 × m
width d = 2.20 µm = 2.20× m
screen distance D = 26.5 cm
I/Imax Yn = 13.0 cm
to find out
the relative intensity
solution
we know that
tanθ = Yn / D
here Yn is the distance from central maximum and D is here distance from screen put all these value
tanθ = 13 / 26.5
θ = 26.13 degree
so
relative intensity of light will be here
I/ Imax = (sinФ/Ф)² ................1
here Ф is angle that is
Ф = πdsinθ / wavelength
Ф = π(2.20×)sin26.13 / ( 755 ×)
Ф = 7.689
so we put Ф = 7.689 in equation 1
I/ Imax = (sinФ/Ф)²
I/ Imax = (sin7.689/7.689)²
I/ Imax = 3.0279 ×
hence the relative intensity is 3.0279 ×