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melomori [17]
2 years ago
12

An object is moved 29 meters with a force of 289 N. what is the work done

Physics
1 answer:
Shtirlitz [24]2 years ago
8 0

Answer:

8381

Explanation:

Workdone=Force x distance

W= 289x 29

W=8381J

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A circular cross section, d = 25 mm, experiences a torque load, T = 25 N·m, and a shear force, V = 85 kN. Calculate the shear st
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Answer:

The correct answer is 231 Mpa i.e option a.

Explanation:

using the equation of torsion we Have

\frac{T}{I_{p}}=\frac{\tau }{r}\\\\\therefore \tau =\frac{T}{I_{p}}\times r

where,

\tau= shear stress at a distance 'r' from the center

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I_{p} = polar moment of inertia of the section

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