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Sedbober [7]
3 years ago
11

a company's stock was elling at $24 a share. A month later, it was selling at $30 a share. What percent is that gain

Mathematics
1 answer:
anzhelika [568]3 years ago
7 0
That would be a 25% gain
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What persent of the model is a circle
enyata [817]
33.3 repeating percent

You set up a proportion

6/18 = x/100

100x6= 600

600÷18 = 33.3 repeating
8 0
3 years ago
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A student scored 84 and 87 on their first two quizzes. Write and solve a compound inequality to find the possible values for a t
BARSIC [14]

Answer:

The score in third quiz must be lie between 84 to 99 inclusive.

Step-by-step explanation:


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3 years ago
Drag the dots to plot (5.5, 4), (-7,1), and (0,–9).<br> y
AURORKA [14]

5.5 always goes between 5 and 6

remember (x,y) one of the dots goes on the exactly on the axis, you have to drag it down to -9 from the y-axis

3 0
2 years ago
A 15 ft. Ladder is placed against a building so that the distance from the top of the ladder to the ground is 10 ft. Find the di
kipiarov [429]

Answer:

  11.2 ft

Step-by-step explanation:

Assuming the building meets the ground at right angles, the right triangle formed has side length 10 ft and hypotenuse 15 ft. Then the other side length (d) is given by the Pythagorean theorem as ...

  d² + 10² = 15²

  d² = 225 -100 = 125

  d = √125 = 5√5 ≈ 11.2 . . . feet

The bottom of the ladder is about 11.2 feet from the building

3 0
3 years ago
Please help! I don't understand how to solve this problem
Ilia_Sergeevich [38]

Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

Assuming an uniform distribution, the standard deviation is given by:

S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The sample size is found solving for n when the margin of error is of M = 0.006, hence:

M = z\frac{\sigma}{\sqrt{n}}

0.006 = 1.96\frac{1.1547}{\sqrt{n}}

0.006\sqrt{n} = 1.96 \times 1.1547

\sqrt{n} = \frac{1.96 \times 1.1547}{0.006}

(\sqrt{n})^2 = \left(\frac{1.96 \times 1.1547}{0.006}\right)^2

n =  142,282.

A sample of 142,282 should be taken, which is not practical as it is too large of a sample.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0
1 year ago
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