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3 years ago

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A student scored 84 and 87 on their first two quizzes. Write and solve a compound inequality to find the possible values for a t

hird quiz score that would give them an average between 85 and 90, inclusive.
A) 80≤n≤98

B) 99≤n≤84

C) 84≤n≤99

D) -0.5≤n≤4.5

1 answer:

BARSIC [14]3 years ago

8 0

Answer:

The score in third quiz must be lie between 84 to 99 inclusive.

Step-by-step explanation:

You might be interested in

To get an A in a course, you must have an average of at least 90% on four tests worth 100 points each. Your scores so far are 85

kondaur [170]

Answer:

A score of 117 is needed, which Is not possible since the test is over 100.

Step-by-step explanation:

The other 3 scores are 85, 94,84 . Let's x be the 4th score he must score.

Therefore ( 85 + 94 + 84 + X)/4 =95

Then 263+X /4 =95

Cross mutiplying 4*95=263+X

Therefore X= 380-263

X= 117 which is not possible since the test score is over 100.

6 0

3 years ago

What is the volume of the sphere?

poizon [28]

Answer: 113.1

Step-by-step explanation:

The formula is $\frac{4}{3}$ $\pi$ $r^{3}$

The radius is 3, and 3 cubed is 27.

Then, 27 x $\pi$ is about 84.82

Finally, 84.82 x $\frac{4}{3}$ is about 113.1

Hope this helps. Please mark as brainliest, thanks!

5 0

3 years ago

Read 2 more answers

Hello. Is there anyone out there who can answer this for me? I truly appreciate it.

Kryger [21]

A. -1

(1,2) and (2,1)
slope = 2 -1 / 1 -2
slope = 1 / -1
slope = -1

7 0

2 years ago

The boy wants to build rectangular beetle cages to study beetle behavior. He wants all the sides on the base of his cages to be

kap26 [50]

Answer:

32 cm by 18 cm

16 cm by 36 cm,

48 cm by 12 cm

24 cm by 24 cm

Step-by-step explanation:

<u><em>The complete question is</em></u>

A boy wants to build rectangular cages. He wants all the sides on the base of his cages to beat least 10 cm long.he also wants the base area to equal 576 cm2. The boy needs help to find all the possible lengths and widths for the base of the cages. He used only whole centimeters, with no fractional parts.what are all the possible dimensions for the rectangular base?

we know that

The number 576 decompose in prime factors is the same that write

$576=(2^6)(3^2)$

To find out possible side lengths, multiply different combinations of these prime numbers together (make sure each pair adds up to 10)

3x3=9cm 2x2x2x2x2x2= 64cm ----> is not a combination (one side is not greater than 10)

3x3x2= 18cm 2x2x2x2x2= 32cm

3x3x2x2= 36cm 2x2x2x2= 16cm

3x2x2= 12cm 3x2x2x2x2= 48cm

3x2x2x2= 24cm 3x2x2x2= 24cm

therefore

32 cm by 18 cm

16 cm by 36 cm,

48 cm by 12 cm

24 cm by 24 cm

3 0

3 years ago

Community college students conduct a survey at their college. They ask "Do you plan to transfer to a university to pursue a bacc

Tamiku [17]

Answer:

$0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697$

$0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903$

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case the conditions we have the conditions to assume a normal distribution for the population proportion since:

np=100*0.8=80 >10 , n(1-p) = 10*(1-0.8) =20 >10

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The estimated proportion is given by $\hat p =\frac{80}{100} =0.8$ . If we replace the values obtained we got:

$0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697$

$0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903$

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

6 0

3 years ago