The kinetic energy of any moving object is
K.E. = (1/2) (mass) (speed)² .
To use this simple formula, the 'mass' has to be in kilograms,
and the 'speed' has to be in meters-per-second.
You can see that we have a slight problem that has to be cleaned up:
The speed in the question is given in "kilometers per hour", but we'll
need it in "meters per second". So let's convert that right now:
(600 km/hour) x (1 hour / 3600 seconds) x (1000 meters / km)
= (600 x 1 x 1000 / 3600) (km-hour-meters / hour-second-km)
= 166.67 meters/second .
Now we're ready to plug numbers into the formula for K.E.
(1/2) (mass) (speed)²
= (1/2) (80,000 kg) (166.67 m/s)²
= (40,000 kg) (27,777.8 m²/s²)
= 1,111,111,111 kg-m²/s²
= 1.1... x 10⁹ Joules (choice D)
Answer:
Part a)
T = 3.96 s
Part b)
T = 1.98 s
Part c)
T = 2.8 s
Explanation:
As we know that time period of spring block system is given as
T = 2.8 s
Part a)
If the mass of the block attached is doubled
then we will have
Part b)
If the spring constant is doubled
then we have
Part c)
If the amplitude is halved but mass and spring constant will remain the same
so here we know that time period does not depends on Amplitude
so we will have
T = 2.8 s
Answer:
Tension maximum =1131.9 N
Tension minimum =868.28 N
Tension at 3/4= 1065.995 N
Explanation:
a)
Given Mass of wrecking ball M1=88.6 Kg
Mass of the chain M2=26.9 Kg
Maximum Tension Tension max=(M1+M2) × (9.8 m/s²)
=(88.6+26.9) × (9.8 m/s²)
=115.5 × 9.8 m/s²
Tension maximum =1131.9 N
b)
Minimum Tension Tension minimum=Mass of the wrecking ball only × 9.8 m/s²
=88.6 × 9.8 m/s²
Tension minimum =868.28 N
c)
Tension at 3/4 from the bottom of the chain =In this part you have to use 75% of the chain so you have to take 3/4 of 26.9
= (3/4 × 26.9)+88.9) × 9.8 m/s²
= (20.175+88.6) × 9.8 m/s²
=(108.775) × 9.8 m/s²
=1065.995 N
