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julia-pushkina [17]
2 years ago
12

Two force of 20N and 40N act at a

Physics
1 answer:
Gala2k [10]2 years ago
7 0

R=√20²+40²+2.20.40 cos 50

R=55 N

R/sin β = F/sin α

55/sin 50 = 40/sin α

α = 33°

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For a specific value of time t the positions of both cars are equal, that is, x=x'. You equal equations (1) and (2) and solve for t:

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