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IrinaK [193]
2 years ago
12

39. Draw a complete free body diagram of a 40 kg plastic crate at rest on a wooden table (us=0.7). The applied force to the righ

t (and horizontal) is 9 N. Label all forces acting on the crate along with the magnitude of the forces.
Physics
1 answer:
Leya [2.2K]2 years ago
4 0

In order to draw the free body diagram, first let's calculate the friction force acting on the crate:

\begin{gathered} F_f=N\cdot\mu \\ F_f=40\cdot9.8\cdot0.7 \\ F_f=274.4\text{ N} \end{gathered}

Since the friction force is greater than the force applied, the crate will not move, and the friction force will be equal to the force applied.

The weight force is equal to 40 * 9.8 = 392 N.

So, drawing the diagram, we have:

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If water is leaking from a certain tank at a constant rate, is it leaking at a rate that is greater than 12 liters per hour?(1 l
Margarita [4]

Answer:

Yes  it is possible because 3.33 is greater than 2.

Explanation:

Given that,

1 liter = 1000 milliliters

Suppose water is leaking from the tank at a rate that is greater than 2 milliliters per second.

We need to change the unit in ml/s

12 lit/hr=\dfrac{12000}{3600}

12 lit/hr=3.33\ ml/s

Hence, Yes  it is possible because 3.33 is greater than 2.

5 0
3 years ago
A box with mass m = 8 kg is pushed x = 10 m across a level floor by a constant applied force F P = 16.27 N. The coefficient of k
vitfil [10]

Answer:

Final speed of the box after it has moved to x = 10 is given as

v = 3.35 m/s

Explanation:

As we know by work energy theorem that work done by all the forces is equal to the change in its kinetic energy

Here work done by external force + work done by friction = change in kinetic energy of the box

so we have

W_{ex} + W_{fric} = \frac{1}{2}mv^2

F x - \mu mg x = \frac{1]{2}mv^2

16.27 (10) - (0.15)(8)(9.8) (10) = \frac{1}{2}(8) v^2

162.7 - 117.6 = 4 v^2

v = 3.35 m/s

4 0
3 years ago
Which part of the electromagnetic spectrum is nearest to radio waves?
svetlana [45]

The part of the electromagnetic spectrum closest to radio waves is <u> microwaves</u>.

The wavelength of radio waves ranges from 10 cm to more than 1 km. The part of the electromagnetic spectrum that occurs closest to the radio waves is called the microwave region.

Microwaves have wavelengths ranging from around 1 mm to 10 cm.

The waves overlap in the region of 10 cm.

Thus, the region of electromagnetic spectrum closest to radiowaves is <u> microwaves.</u>

3 0
3 years ago
Read 2 more answers
At 20∘C20 ∘ C, the hole in an aluminum ring is 2.500 cm in diameter. You need to slip this ring over a steel shaft that has a ro
Feliz [49]

Answer:

238.75⁰C .

Explanation:

coefficient of linear thermal expansion of aluminum and steel is  23 x 10⁻⁶ K⁻¹ and 12 x 10⁻⁶ K⁻¹ respectively .

Rise in temperature be Δ t .

Formula for linear expansion due to heat is as follows

l = l₀ ( 1 + α x Δt )

l is expanded length , l₀ is initial length , α is coefficient of linear expansion and  Δt is increase in temperature .

For aluminum

l = 2.5 ( 1 +  23 x 10⁻⁶ Δt )

For steel

l = 2.506 ( 1 + 12 x 10⁻⁶ Δt )

Given ,

2.5 ( 1 +  23 x 10⁻⁶ Δt ) = 2.506 ( 1 + 12 x 10⁻⁶ Δt )

1 +  23 x 10⁻⁶ Δt = 1.0024 ( 1 + 12 x 10⁻⁶ Δt )

1 +  23 x 10⁻⁶ Δt = 1.0024   + 12.0288 x 10⁻⁶ Δt

10.9712 x 10⁻⁶ Δt = .0024

Δt = 218.75

Initial temperature = 20⁰C

final temperature = 218.75 + 20 = 238.75⁰C .

8 0
3 years ago
What graph would best represent acceleration as a function of mass when a constant force is applied?
Alex17521 [72]

The graphs of the acceleration as a function of mass and of the acceleration as a function of force are in attachment.

Explanation:

To answer both parts of the question, we refer to Newton's second law, which states that:

F=ma

where

F is the net force on an object

m is the mass of the object

a is its acceleration

a)

To answer this part, we re-arrange the previous equation as follows:

a=\frac{F}{m}

Therefore, we notice that if a constant force is applied, the acceleration is inversely proportional to the mass of the object:

a \propto \frac{1}{m}

this means that if the mass increases, the acceleration decreases, and if the mass decreases, the acceleration increases.

In a graph of acceleration vs mass, the curve representing this relationship would be a hyperbole. The graph is shown as the first graph in the attached picture.

b)

As before, we re-arrange the previous equation as follows:

a=\frac{F}{m}

Here we notice that if the object has a constant mass, the acceleration is directly proportional to the force applied on the object:

a \propto F

this means that when the force increases, the acceleration increases, and when the force decreases, the acceleration decreases.

In a graph of acceleration vs force, the curve representing this relationship would be a straight line, as shown in the second graph in the attached picture.

Learn more about Newton's second law of motion here:

brainly.com/question/3820012

#LearnwithBrainly

6 0
3 years ago
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