Louise wants to factorize completely the given polynomial ![4x^{3}+12x^{2}+5x+15](https://tex.z-dn.net/?f=%204x%5E%7B3%7D%2B12x%5E%7B2%7D%2B5x%2B15%20)
Grouping first, second terms together and third, fourth terms together
= ![4x^{3}+12x^{2}+5x+15](https://tex.z-dn.net/?f=%204x%5E%7B3%7D%2B12x%5E%7B2%7D%2B5x%2B15%20)
Taking
common from first and second terms of the given expression and taking 5 common from the third and fourth terms.
=![=4x^{2}(x+3)+5(x+3)](https://tex.z-dn.net/?f=%20%3D4x%5E%7B2%7D%28x%2B3%29%2B5%28x%2B3%29%20)
Taking (x+3) common from the given expression,
=
is the completely factored form.
yes It has at least one set of parallel lines
Answer:
![-\frac{5}{6}](https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D)
Step-by-step explanation:
Use the slope formula :![\frac{y2-y1}{x2-x1}](https://tex.z-dn.net/?f=%5Cfrac%7By2-y1%7D%7Bx2-x1%7D)
-1/2 is y2, 3/4 is y1, 5/6 is x2, and -2/3 is x1.
![\frac{-1/2-3/4}{5/6-(-2/3)}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%2F2-3%2F4%7D%7B5%2F6-%28-2%2F3%29%7D)
![\frac{-5/4}{5/6+2/3}](https://tex.z-dn.net/?f=%5Cfrac%7B-5%2F4%7D%7B5%2F6%2B2%2F3%7D)
![\frac{-5/4}{9/6}](https://tex.z-dn.net/?f=%5Cfrac%7B-5%2F4%7D%7B9%2F6%7D)
÷ ![\frac{9}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B6%7D)
• ![\frac{6}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B9%7D)
• ![\frac{3}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B9%7D)
![-\frac{5}{6}](https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D)
Hope this helps! Let me know if I got it wrong.
Answer:
B
Step-by-step explanation: