-x + 8 = x - 10
8 - x = x - 10
8 = x - 10 + x
8 = 2x - 10
8 + 10 = 2x
18 = 2x
18/2 = x
9 = x
x = 9
Solution :
Given


Let the initial approximation is 
So by Newton's method, we get






are identical up to eight decimal places.
The approximate real root is x ≈ 1.32471795
∴ x = 1.32471795
Answer: 294
Step-by-step explanation:
81-25+800/2=
81-25+400=
81-375= 294
1060 / 48 = 22.08 = 22.1
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