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3 years ago

Which type of work is an electrical engineer most likely to do?

Engineering

2 answers:

Elena-2011 [213]3 years ago

7 0

Answer:

its a

Explanation:

bcz electrical engineering is transponetworks etc

IRISSAK [1]3 years ago

5 0

I believe A is the answer: creat materials for electrical cables

Hope this helps you have a great day

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To measure an object accurately, what point on the ruler would you align with the object edge

Firlakuza [10]

Answer:

Along the zero to measure an object on a ruler

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3 years ago

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Find the minimum sum of products expression using Quine-McCluskey method of the function. F(A,B,C,D)= Î£ m(1,5,7,8,9,13,15)+ Î£

kompoz [17]

Answer:

Digital electronics deals with the discrete-valued digital signals. In general, any electronic system based on the digital logic uses binary notation (zeros and ones) to represent the states of the variables involved in it. Thus, Boolean algebraic simplification is an integral part of the design and analysis of a digital electronic system.

Explanation:

Hi please follow me also I you can and thanks for the points. Have a good day.

5 0

3 years ago

A construction company distributes its products by trucks loaded at its loading station. A backacter in conjunction with trucks

blagie [28]

Answer:

a) $L = 1.5$

$L_q = 0.9$

$W = \dfrac{1 }{8 } \, hour$

$W_q = \dfrac{3}{40 } \, hour$

$P = \dfrac{3}{5 }$

b) The new backacter should be recommended

c) The additional backacter should not be deployed

Explanation:

a) The required parameters are;

L = The number of customers available

$L = \dfrac{\lambda }{\mu -\lambda }$

μ = Service rate

$L_q$ = The number of customers waiting in line

$L_q = p\times L$

W = The time spent waiting including being served

$W = \dfrac{1 }{\mu -\lambda }$

$W_q$ = The time spent waiting in line

$W_q = P \times W$

P = The system utilization

$P = \dfrac{\lambda }{\mu }$

From the information given;

λ = 12 trucks/hour

μ = 3 min/truck = 60/3 truck/hour = 20 truck/hour

Plugging in the above values, we have;

$L = \dfrac{12 }{20 -12 } = \dfrac{12 }{8 } = 1.5$

$P = \dfrac{12 }{20 } = \dfrac{3}{5 }$

$L_q = \dfrac{3}{5 } \times \dfrac{3}{2 } = \dfrac{9}{10 } = 0.9$

$W = \dfrac{1 }{20 -12 } = \dfrac{1 }{8 } \ hour$

$W_q = \dfrac{3}{5 } \times \dfrac{1}{8 } = \dfrac{3}{40 } \, hour$

(b) The service rate with the new backacter = 1.5 minutes/truck which is thus;

μ = 60/1.5 trucks/hour = 40 trucks/hour

$P = \dfrac{12 }{40 } = \dfrac{3}{10}$

$W = \dfrac{1 }{40 -12 } = \dfrac{1 }{38 } \, hour$

$W_q = \dfrac{3}{10 } \times \dfrac{1}{38 } = \dfrac{3}{380 } \, hour$

λ = 12 trucks/hour

Total cost = $mC_s + \lambda WC_w$

m = 1

$C_s$ = GH¢ = 1300

$C_w$ = 400

Total cost with the old backacter is given as follows;

$1 \times 1000 + 12 \times \dfrac{1}{8} \times 400 = \$ 1,600.00$

Total cost with the new backacter is given as follows;

$1 \times 1300 + 12 \times \dfrac{1}{38} \times 400 = \$ 1,426.32$

The new backacter will reduce the total costs, therefore, the new backacter is recommended.

Here μ = 3 min/ 2 trucks = 2×60/3 truck/hour = 40 truck/hour

$\therefore W = \dfrac{1 }{40 -12 } = \dfrac{1 }{38 } \, hour$

Total cost with the one backacter is given as follows;

$1 \times 1000 + 12 \times \dfrac{1}{8} \times 400 = \$ 1,600.00$

Total cost with two backacters is given as follows;

$2 \times 1000 + 12 \times \dfrac{1}{38} \times 400 = \$ 2,126.32$

The additional backacter will increase the total costs, therefore, it should not be deployed.

6 0

3 years ago

Explain working mechanism of pressure relief valve.

BigorU [14]

Answer:

The pressure is relieved by allowing the pressurised fluid to flow from an auxiliary passage out of the system.

Explanation:

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4 years ago

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A fully braced structural member in a building is subjected to several different loads, including roof loads of D = 5 k and L_r

allochka39001 [22]

Answer: 37.4K

Explanation:

See attachment

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3 years ago