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kipiarov [429]
4 years ago
6

A suspension of Bacillus subtilis cells is filtered under constant pressure for recovery of protease. A pilot-scale filter is us

ed to measure filtration properties. The filter area is 0.25 m2, the pressure drop is 360 mmHg, and the filtrate viscosity is 4.0 cP. The cell suspension deposits 22 g cake per liter of filtrate. The following data are measured: (Hints: Change the unit to standard units)
Time (min)​​ 2 ​ 3​ 6 ​ 10 ​15 ​20

Filtrate volume

(L)

10.8 12.1 18.0 21.8 28.4 32

a) Determine the specific cake resistance and filter medium resistance.
b) What size filter is required to process 4000 L cell suspension in 30 min at a pressure drop of 360 mm Hg?

Engineering
1 answer:
sattari [20]4 years ago
7 0

The answer & explanation for this question is given in the attachment below.

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3 0
3 years ago
One of the most important parts about creating great photographs starts with choosing what to photograph
Sliva [168]
Yeah that is important
7 0
3 years ago
Your friend offers to pay you $3,000 five years from now. You'd prefer the money now so you can put it in a bank account at 8% i
zepelin [54]

Answer:

  $958.25

Explanation:

  PV = FV(1 +r)^(-t) . . . . present value of an amount earning rate r compounded annually for t years

  PV = $3000(1.08^-5) ≈ $2041.75

The equivalent present value is $2041.75.

__

This amount is less than the offered amount by ...

  $3000 -2041.75 = $958.25

She should pay you $958.25 less in order to make the offers equivalent.

4 0
3 years ago
State the two Carnot corollaries (principles)
Salsk061 [2.6K]

Answer  and Explanation:

The two principles or corollaries of Carnot Theorem are listed below:

1). The efficiencies of all the reversible heat engines between any two thermal reservoirs working between the same temperatures will be equal to each other.

2). For every Carnot engine working between any two thermal reservoirs will have the same efficiency independent of the operating conditions and the nature of working substance. It only depends on the temperature of the thermal energy reservoirs.

8 0
4 years ago
While walking across campus one windy day, an engineering student speculates about using an umbrella as a "sail" to propel a bic
makvit [3.9K]

Answer:

Given data:\\While walking across campus one windy day\\Frontal area, \(A=0.3 m ^{2}\)\\Wind speed \(V=24 Km / hr\)\\The drag coefficient \(C_{D, b}=1.2\)\\The combined mass \(m=75 kg\)\\Umbrella diameter, \(D=1.22 m\)\\Velocity of wind \(V=24 \frac{ km }{ hr }\)\\The rolling resistance \(C_{R}=0.75 \%\)

Solution:

Note: Refer the diagram

Basic equation:\\'s law of motion: \(\sum F_{x}=m a_{x}\)\\Lift coefficient, \(C_{L}=\frac{F_{L}}{\frac{1}{2} \rho V^{2} A_{p}}\)\\Drag coefficient, \(C_{D}=\frac{F_{D}}{\frac{1}{2} \rho V^{2} A_{p}}\)

From force balance equation:\\\(\sum F_{x}=F_{D}-F_{R}=0\)\\But \(F_{D}=\left(C_{D, \alpha} A_{u}+C_{D, B} A_{b}\right) \frac{1}{2} \rho\left(V_{\nu}-V_{b}\right)^{2}\)\(F_{R}=C_{R} m g\)\\Area of the Umbrella \(A_{u}=\frac{\pi D_{u}^{2}}{4}\)\(A_{x}=\frac{\pi \times 1.22^{2}}{4} m ^{2}\)\(A_{v}=1.17 m ^{2}\)

Drag coefficient data for selected objects table at

Hemisphere (open end facing flow), C_{D, x}=1.42

Substituting all parameters,

\begin{aligned}&F_{R}=0.0075 \times 75 \times 9.81\\&F_{R}=5.52 N\end{aligned}

Then,

\begin{aligned}&V_{b}=V_{w}-\left[\frac{2 F_{R}}{\rho\left(C_{D, w} A_{w}+C_{D, B} A_{b}\right)}\right]^{\frac{1}{2}} \dots\\&V_{w}=24 \times 1000 \times \frac{1}{3600}\\&V_{w}=6.67 \frac{ m }{ s }\end{aligned}

And the equation becomes,

\begin{aligned}&V_{b}=6.67-\left[\frac{2 \times 5.52}{1.23(1.42 \times 1.17+1.2 \times 0.3)}\right]^{\frac{1}{2}}\\&V_{b}=6.67-2.11\\&V_{b}=4.56 \frac{ m }{ s }\end{aligned}

Thus the floyds travels at 68.3^{\circ}wind speed.

7 0
4 years ago
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