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insens350 [35]
3 years ago
10

Please help ! Thanks you

Chemistry
1 answer:
Allushta [10]3 years ago
7 0

Answer:

See Explanation

Explanation:

According to Avogadro's law;

V1/n1 = V2/n2

V1 = 5.0 L

n1 = 15.0 moles

V2= ?

n2 = 30.0 moles

V1n2 = V2n1

V2 = 5 * 30/15

V2 = 10 L

2) 1 mole of N2 occupies 22.4 L

3 moles of N2 occupies 3 * 22.4/1 = 67.2 L

3) 1 mole of O2 occupies 22.4 L

x moles occupies 201.6 L

x = 1 mole* 201.6 L/22.4 L

x = 9 moles

4) Density of a gas = mass/volume

Density of a gas = 39.95 g/22.4 L = 1.78 g/L

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What is the pH of a solution with an H3O+ concentration of 5.67 x 10-4 M?
Valentin [98]

Answer:

<h2>3.25 </h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ { H_3O}^{+}]

From the question we have

ph =  -  log(5.67 \times  {10}^{ - 4} )  \\  = 3.2464

We have the final answer as

<h3>3.25 </h3>

Hope this helps you

3 0
3 years ago
What volume of carbon dioxide gas can be collected from
alisha [4.7K]

Answer:

1.22 L of carbon dioxide gas

Explanation:

The reaction that takes place is:

  • CaCO₃ + HCl → CaCl₂ + CO₂ + H₂O

First we <u>determine which reactant is limiting</u>:

  • Calcium carbonate ⇒ 10.0 g CaCO₃ ÷ 100 g/mol = 0.10 mol CaCO₃
  • Hydrochloric acid ⇒ 0.100 L * 0.50 M = 0.05 mol HCl

So HCl is the limiting reactant.

Now we calculate the moles of CO₂ produced:

  • 0.05 mol HCl * \frac{1molCO_{2}}{1molHCl} = 0.05 mol CO₂

Finally we use PV=nRT to <u>calculate the volume</u>:

  • P = 1 atm
  • n = 0.05 mol
  • T = 25 °C ⇒ 25 + 273.16 = 298.16 K

1 atm * V = 0.05 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

  • V = 1.22 L
7 0
3 years ago
When 1 mol of KBr(s) decomposes to its elements, 394 kJ of heat is absorbed. (a) Write a balanced thermochemical equation.
VladimirAG [237]

The balanced thermochemical equation is

KBr ------- K + 1/2 Br2

<h3>What is thermochemical equation? </h3>

A Thermochemical Equation is defined as the balanced stoichiometric chemical equation which includes the enthalpy change, ΔH.

The chemical equation for the decomposition of potassium bromide to its constituent elements bromine ans potassium :

KBr ----- K + Br2

The balanced thermochemical equation of the decomposition of potassium bromide to its constituent elements potassium and bromide as follows

KBr ------- K + 1/2 Br2

As the heat is absorbed in this reaction therefore, heat is positive.

Thus, we concluded that the balanced thermochemical equation is

KBr ------- K + 1/2 Br2

learn more about thermochemical equation:

brainly.com/question/2733624

#SPJ4

8 0
2 years ago
A 44.0 g sample of an unknown metal at 99.0 oC was placed in a constant-pressure calorimeter of negligible heat capacity contain
tatiyna

Answer:

C_m=0.474\frac{J}{g\°C}

Explanation:

Hello.

In this case, since this is a system in which the water is heated up and the metal is cooled down in a calorimeter which is not affected by the heat lose-gain process, we can infer that the heat lost by the metal is gained be water, it means that we can write:

Q_m=-Q_w

Thus, in terms of masses, specific heats and temperatures we can write:

m_mC_m(T_{eq}-T_m)=-m_wC_w(T_{eq}-T_w)

Whereas the equilibrium temperature is the given final temperature of 28.4 °C and we can compute the specific heat of the metal as shown below:

C_m=\frac{-m_wC_w(T_{eq}-T_w)}{m_m(T_{eq}-T_m)}

Plugging the values in and since the density of water is 1.00 g/mL so the mass is 80.0g, we obtain:

C_m=\frac{-80.0g*4.184\frac{J}{g\°C} (28.4\°C-24.0\°C)}{44.0g(28.4\°C-99.0\°C)}\\\\C_m=0.474\frac{J}{g\°C}

Best regards!

6 0
3 years ago
5,6-dimethyl-2-heptyne <br><br> Due in 1 hr pls help me
mina [271]

Answer:

Please see the attached pictures.

Explanation:

☆ To ensure that each carbon has 4 bonds, fill the other bonds with Hs.

4 0
3 years ago
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