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insens350 [35]
3 years ago
10

Please help ! Thanks you

Chemistry
1 answer:
Allushta [10]3 years ago
7 0

Answer:

See Explanation

Explanation:

According to Avogadro's law;

V1/n1 = V2/n2

V1 = 5.0 L

n1 = 15.0 moles

V2= ?

n2 = 30.0 moles

V1n2 = V2n1

V2 = 5 * 30/15

V2 = 10 L

2) 1 mole of N2 occupies 22.4 L

3 moles of N2 occupies 3 * 22.4/1 = 67.2 L

3) 1 mole of O2 occupies 22.4 L

x moles occupies 201.6 L

x = 1 mole* 201.6 L/22.4 L

x = 9 moles

4) Density of a gas = mass/volume

Density of a gas = 39.95 g/22.4 L = 1.78 g/L

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The answer is 4.9 moles of salt will be needed to add to 1 kg of water to change the boiling point by 5 °C.

<h3>What is Boiling Point Elevation ?</h3>

Boiling point elevation is the phenomenon that occurs when the boiling point of a liquid (a solvent) is increased when another compound is added, such that the solution has a higher boiling point than the pure solvent.

Boiling point elevation occurs whenever a non-volatile solute is added to a pure solvent.

ΔT = i * Kb * m

where m, Kb and i are the molality of solution, ebullioscopic constant and Van't Hoff factor respectively

The data given in the question is ΔT = 5 °C

mass of solvent = 1 kg

Kb = 0.51 °C/(mol/kg)

Van't Hoff Factor for NaCl is 2

Substituting the values in the above equation

\rm 5 = \rm\dfrac{2\times0.51\times moles \;of \;salt}{1}

\rm moles \;of \;salt = \rm\dfrac{5}{2\times0.51}

moles of salt = 4.9

Therefore 4.9 moles of salt will be needed to add to 1 kg of water to change the boiling point by 5 °C.

To know more about Boiling point elevation

brainly.com/question/17218953

#SPJ1

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