You have 50 g of radioactive C-14. The half-life of C-14 is 5,730 years. How many grams would you have left after 5,730 years?

The reaction described by the equation CH 3 Cl + NaOH → CH 3 OH + NaCl follows the second-order rate law, rate = k [ CH 3 Cl ] [

fredd [130]

Answer:

The rate is $4,5 \times 10^{-5}\frac{mole}{Ls}$

Explanation:

Stoichiometry

$CH_{3}Cl+NaOH \rightarrow CH_{3}OH+NaCl$

Kinetics

$-r_{A}=k \times [CH_{3}Cl] \times [NaOH]$

The rate constant K can be calculated by replacing with the initial data

$1 \times 10^{-4}\frac{mole}{Ls}=k \times [0,2M] \times [1,0M] =5 \times 10^{-4}\frac{L}{mole s}$

Taking as a base of calculus 1L, when half of the $CH_{3}Cl$ is consumed the mixture is composed by

$0,1 mole CH_{3}Cl$ (half is consumed)

$0,9 mole NaOH$ (by stoicheometry)

$0,1 mole CH_{3}OH$

$0,1 mole NaCl$

Then, the rate is

$-r_{A}=5 \times 10^{-4} \frac{L}{mole s}\times 0,1M \times 0,9 M=4,5 \times 10^{-5}\frac{mole}{Ls}$

The reaction rate decreases because there’s a smaller concentration of reactives.

6 0

3 years ago

Solve as soon as possible with detailed step by step explanation

scoundrel [369]

Mr. Jones's prescription calls for 1.04 tablets per day. Based on this information, how many tablets should Mr. Jones take per day? a) 1.25 O b) 1.5 c) 1 O d) 2

8 0

3 years ago

An atom of sodium 23 Na(23) has a net charge of plus 1 identify the number of protons, neutrons, and electrons in the atom

prohojiy [21]

Sodium 23 has 11 electrons 11 protons and 12 neutrons

7 0

3 years ago

2Na+S→Na2S

Sedbober [7]

Answer:

2.0 moles S

Explanation:

To find the number of moles of S, you need to convert the moles Na to moles S via the mole-to-mole ratio. This ratio is represented by the coefficients in the balanced equation. Because you wish to find moles S, you want to put this number in the numerator. Because you want to eliminate the moles Na, this number should be in the denominator.

2 Na + 1 S ---> Na₂S

4.0 moles Na 1 mole S
---------------------- x --------------------- = 2.0 moles S
2 moles Na

3 0

2 years ago

The decomposition of HBr(g) into elemental species is found to have a rate constant of 4.2 ×10−3atm s−1. If 2.00 atm of HBr are

Dennis_Churaev [7]

Answer:

7,94 minutes

Explanation:

If the descomposition of HBr(gr) into elemental species have a rate constant, then this reaction belongs to a zero-order reaction kinetics, where the reaction rate does not depend on the concentration of the reactants.

For the zero-order reactions, concentration-time equation can be written as follows:

[A] = - Kt + [Ao]

where:

[A]: concentration of the reactant A at the t time,
[A]o: initial concentration of the reactant A,
K: rate constant,
t: elapsed time of the reaction

To solve the problem, we just replace our data in the concentration-time equation, and we clear the value of t.

Data:

K = 4.2 ×10−3atm/s,

[A]o=[HBr]o= 2 atm,

[A]=[HBr]=0 atm (all HBr(g) is gone)

We clear the incognita :

[A] = - Kt + [Ao]............. Kt = [Ao] - [A]

t = ([Ao] - [A])/K

We replace the numerical values:

t = (2 atm - 0 atm)/4.2 ×10−3atm/s = 476,19 s = 7,94 minutes

So, we need 7,94 minutes to achieve complete conversion into elements ([HBr]=0).

6 0

3 years ago

You have 50 g of radioactive C-14. The half-life of C-14 is 5,730 years. How many grams would you have left after 5,730 years? ​

You have 50 g of radioactive C-14. The half-life of C-14 is 5,730 years. How many grams would you have left after 5,730 years?