= 9.1 × 10^6
(scientific notation)
= 9.1e6
(scientific e notation)
= 9.1 × 10^6
(engineering notation)
(million; prefix mega- (M))
= 9100000
<span>(real number)</span>
Volume of a sphere = 4/3 x pi x r^3
When put a fraction of volume constant 4/3 x pi cancels out.
So only cube of radii remains.
Radius of proton = 10^-15 m (Fact; remember it)
Radius of total Hydrogen atom = 0.529 × 10^−10 m
Fraction of Volumes : R'^3/R^3 = (R/R)^3
Fraction = ((10^-15)/(0.529 × 10^−10m.))^3= (1/52900)^3 =
6.755 x 10^-15
I uhhh would answer but this is actually confusing
The given chemical reaction is:
The standard heats of formation of 
are:
Δ
) = -285.8kJ/mol[/tex]
Δ
) = -187.6 kJ/mol[/tex]
Calculating the change in heat:
Δ
=∑ΔH
-∑ΔH
= [{2 * (-285.8 kJ/mol)} -{2*(-187.6 kJ/mol)}]
= -196.4 kJ/mol
Therefore, the change in enthalpy for the given reaction is -196.4 kJ/mol
