Answer:
the work done on the car is 7,500 J.
Explanation:
Given;
distance traveled by the car, d = 150 m
applied force, F = 50 N
The work done on the car is calculated as;
W = F x d
W = 50 N x 150 m
W = 7,500 J
Therefore, the work done on the car is 7,500 J.
Answer: It is the ratio of solute in a solution to either solvent or total solution.
Explanation:
The water runs out the holler and through the creek an then the molecules sedimentate
Would eventually stop when it doesn't have anymore potential energy
Answer:
51.54 m/s
Explanation:
Applying,
Law of conservation of momentum,
Total momentum before collision = Total momentum after collision
mu+m'u' = mv+m'v'.................... Equation 1
Where m = mass of the head of the golf club, m' = mass of the gulf ball, u = initial velocity of the head of the gulf club, u' = initial velocity of the gulf ball, v = final velocity of the head of a gulf club, v' = final velocity of the gulf ball
From the question,
Given: m = 151 g = 0.151 kg, u = 43.9 m/s, m' = 46 g = 0.046 kg, u' = 0 m/s (at rest), v = 28.2 m/s
Substitute these values into equation 1
0.151(43.9)+0.046(0) = 0.151(28.2)+0.046(v')
solve for v'
6.6289+0 = 4.2582+0.046v'
0.046v' = 6.6289-4.2582
0.046v' = 2.3707
v' = 2.3707/0.046
v' = 51.54 m/s