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ruslelena [56]
3 years ago
13

Biologists have studied the running ability of the northern quoll, a marsupial indigenous to Australia. In one set of experiment

s, they studied the maximum speed that quolls could run around a curved path without slipping. One quoll was running at 2.6 m/s around a curve with a radius of 0.80 m when it started to slip. What was the coefficient of static friction between the quails feet and the ground in this trial?
Physics
1 answer:
Drupady [299]3 years ago
4 0

Answer:

u_K=0.862

Explanation:

The force of friction between the quails feet and the ground is:

F=m*a

F_K=m*a

F_K=u_k*m*g

u_K*m*g=m*a_c

u_K*g=a

u_K=\frac{a_c}{g}

a_c=\frac{v^2}{r}

So the coefficient of static is solve

u_K=\frac{\frac{v^2}{r}}{g}

u_K=\frac{v^2}{r*g}=\frac{(2.6m/s)^2}{0.80m*9.8m/s^2}

u_K=0.862

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Answer:

O is an element whilst H2O2 is a compound.

Explanation:

O is an element. You can find it on the periodic table. H2O2 is composed of both H and O. Thus, H2O2 is a compound.

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A 200g of iron at 120 degrees and a 150 g piece of copper at -50 degrees are dropped into an insulated beaker containing 300 g o
kodGreya [7K]

Answer:

T = 15.03°C

Explanation:

given data:

copper specific heat = Sc = 0.385 J/g °C

iron specific iron = Si = 0.450 J/g °C

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(m*S*\Delta T)_{copper} +(m*S*\Delta T)_ {iron} +(m*S*\Delta T)_ {ethanol} = 0

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57.75( T - (-50)) + 0.90(T - 120) +738(T -20) = 0

57.75T + 2887.5 + 0.90T - 108 + 738T - 14760 = 0

57.75T + 0.90T+738T = - 2887.5 + 108+14760

796.65T= 11980.5

T = 15.03°C

4 0
3 years ago
Make the following prefix conversions.<br> 0.001s =ms
Free_Kalibri [48]

Answer:

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Explanation:

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