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ruslelena [56]
3 years ago
13

Biologists have studied the running ability of the northern quoll, a marsupial indigenous to Australia. In one set of experiment

s, they studied the maximum speed that quolls could run around a curved path without slipping. One quoll was running at 2.6 m/s around a curve with a radius of 0.80 m when it started to slip. What was the coefficient of static friction between the quails feet and the ground in this trial?
Physics
1 answer:
Drupady [299]3 years ago
4 0

Answer:

u_K=0.862

Explanation:

The force of friction between the quails feet and the ground is:

F=m*a

F_K=m*a

F_K=u_k*m*g

u_K*m*g=m*a_c

u_K*g=a

u_K=\frac{a_c}{g}

a_c=\frac{v^2}{r}

So the coefficient of static is solve

u_K=\frac{\frac{v^2}{r}}{g}

u_K=\frac{v^2}{r*g}=\frac{(2.6m/s)^2}{0.80m*9.8m/s^2}

u_K=0.862

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Answer:

a. one-half as great

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Since the two lifters do the same work at different time, let us estimate their power;

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U_B = u_B(A)(L)\\\\U_B = 6.366*10^6(\pi * 0.031^2)(0.26) \\\\U_B = 4997.69 J\\\\U_B = 5 \ KJ\\

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