The first: alright, first: you draw the person in the elevator, then draw a red arrow, pointing downwards, beginning from his center of mass. This arrow is representing the gravitational force, Fg.
You can always calculate this right away, if you know his mass, by multiplying his weight in kg by the gravitational constant

let's do it for this case:

the unit of your fg will be in Newton [N]
so, first step solved, Fg is 637.65N
Fg is a field force by the way, and at the same time, the elevator is pushing up on him with 637.65N, so you draw another arrow pointing upwards, ending at the tip of the downwards arrow.
now let's calculate the force of the elevator

so you draw another arrow which is pointing downwards on him, because the elevator is accelating him upwards, making him heavier
the elevator force in this case is a contact force, because it only comes to existence while the two are touching, while Fg is the same everywhere
Answer:
B. 4 m/s
Explanation:
v=d/t
Running for 300 m at 3 m/s takes 100 seconds and running at 300 m at 6 m/s takes 50 seconds. 100 s + 50 s = 150 s (total time). Total distance is 600 m, so 600 m/ 150 s = 4 m/s.
Answer:
Energy = 780 Joules
Explanation:
Given the following data;
Power = 78 Watts
Time = 10 seconds
To find the energy transferred;
Energy refers to the amount or quantity of power which is being consumed by an individual, group of people or organization over a specific period of time.
Mathematically, energy is given by the formula;
Energy = power * time
Energy = 78 * 10
Energy = 780 Joules
Therefore, the amount of energy the turbine transferred is 780 Joules
Hdghehwhevevwgwhhwvsvsvsiosjwbwbwhshbshs
Answer:
0
Explanation:
F1 = G•2.2•4.66/3² (pointed right)
F2 = G•2.2•4.66/3² (pointed left)
subtract the two to get zero