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Hitman42 [59]
3 years ago
8

Which of the following actions is best understood using Einstein's concepts rather than Newtonian physics?

Physics
2 answers:
klio [65]3 years ago
6 0

Answer:

D.The radioactive decay of an atom

Explanation:

Newtonian physics is related to particle physics in which we deal with the properties exhibit by particles like

1). Momentum conservation

2). Particle collision theory

3). Particle dynamics

So as per all above theory we can use momentum conservation and energy conservation to find the different phenomenon.

But we could not explain the decay of radioactive atom using all above theory as it is due to unstability of nucleus and it is only explained by Einstein theory of relativity.

E = \Delta m c^2

So here correct answer would be

D.The radioactive decay of an atom

LekaFEV [45]3 years ago
5 0
The best and most correct answer among the choices provided by the question is <span>D.The radioactive decay of an atom</span> <span>.
</span>


Hope my answer would be a great help for you.    
If you have more questions feel free to ask here at Brainl
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A single loop of nickel wire, lying flat in a plane, has an area of 7.40 cm^2 and a resistance of 2.40 Ω. A uniform magnetic fie
ale4655 [162]

Explanation:

It is given that,

Area of nickel wire, A=7.4\ cm^2=7.4\times 10^{-4}\ m^2

Resistance of the wire, R = 2.4 ohms

Initial value of magnetic field, B_1=0.5\ T

Final magnetic field, B_2=3\ T

Time, t = 1.12 s

Let I is the induced current in the loop of wire over this time. Te emf induced in the wire is given by Faraday's law as :

\epsilon=-\dfrac{d\phi}{dt}

\epsilon=-\dfrac{d(BA)}{dt}

\epsilon=-A\dfrac{d(B)}{dt}

\epsilon=-A\dfrac{B_2-B_1}{t}

\epsilon=-7.4\times 10^{-4}\times \dfrac{3-0.5}{1.12}

\epsilon=1.65\times 10^{-3}\ V

Induced current in the loop of wire is given by :

I=\dfrac{\epsilon}{R}

I=\dfrac{1.65\times 10^{-3}}{2.4}

I=6.87\times 10^{-4}\ A

So, the induced current in the loop of wire over this time is 6.87\times 10^{-4}\ A. Hence, this is the required solution.

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