Answer:
Time=3.1 seconds
Explanation:
Given data
Distance S=20 m
Velocity v=10×Sin60°
To find
Time after release
Solution
From equation of simple motion we know that
Using the convention that down is positive then
Apply Quadratic formula to solve t
Ignoring the -ve root then we have
t=3.1 seconds
If energy input remains
constant and voltage remains the same in a circuit, but the current decreases,
the power has increased. It is presented in the equation P = VI where P is
power, V is voltage and I is current.
Answer:
(a). = 5.43
(b). 13
(C) 0
Explanation:
part A:
φ(outside) = ∬B(outside) dS
note that;
φ(sum) = 2[φ(outside) + φ(inside).
then, we say
φ(outside) = ∫ μI/ 2πr dr (taking boundaries at R - d/2 and d/2.
μI/2πr dr= μI/2πr ln 2R- d/d
= 1.26× 1) ^-6 ×10 ln 40-2.5/2.5.
= 5.43 μWb.
magnetic flux in the conductor can be calculated from magnetic induction as integral of d/2 to R
please note that dS= 1. dr
φ (inside) = B(inside) dS
∫2μIr/ π d^2 dV.
μI/πd2 r^2 (at boundary d/2 and 0)
μI/4π
= 1.26×10^-6 ×10/4π.
= 1.0032 μWb .
where B(inside) = μI(inside)/ 2πr and I= Ir^2/ (d/2) ^2.
φ(sum)= φ(outside + inside)
=2(5.42 + 1.0032
= 13μWb
(c). is zero