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3 years ago

Need help with work

Mathematics

1 answer:

Sonbull [250]3 years ago

5 0

Answer:

Step-by-step explanation:

I don’t want to help you :)

We can use the Pythagorean Theorem to solve the triangle for x.

$25^2=14^2+x^2$

$625=196+x^2$

$x^2=429$

$x=\sqrt{429}$

x≈20.7

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The area of an equilateral triangle is given by A =3^1/2/4s^2. Find the length of the side s of an equilateral triangle with an

yan [13]

Answer:

The length of the side of an equilateral traingle $s=2\sqrt{2}$ inches

Step-by-step explanation:

Given that the area of an equilateral triangle is given by

$A=3^\frac{1}{2}s^2$

It can be written as

$a=\frac{\sqrt{3}}{4} s^2$ Square inches (1)

To find the length of the side s os an equilateral triangle

Given that area of an equilateral triangle is $12^\frac{1}{2}$ square inches

It can be written as

$A=12^\frac{1}{2}$

$A=\sqrt{12}$ square inches

It can be written as

$A=12^\frac{1}{2}$

$A=\sqrt{12}$ square inches (2)

Now comparing equations (1) and (2) we get

$\frac{\sqrt{3}}{4}s^2=\sqrt{12}$

$\frac{\sqrt{3}}{4}s^2=\sqrt{4\times 3}$

Dividing by $\frac{\sqrt{3}}{4}$ on both sides we get

$\frac{\frac{\sqrt{3}}{4}s^2}{\frac{\sqrt{3}}{4}}=\frac{2\sqrt{3}}{\frac{\sqrt{3}}{4}}$

$\frac{\sqrt{3}}{4}s^2\times\frac{4}{\sqrt{3}}=2\sqrt{3}\times\frac{4}{\sqrt{3}}$

$s^2=8$

$s=\sqrt{8}$

Therefore $s=2\sqrt{2}$ inches

Therefore the length of the side of an equilateral traingle $s=2\sqrt{2}$ inches

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3 years ago

Lhvijhhhrjdjnrkdksns jsbsjsjsks jsnsj

emmasim [6.3K]

Answer:

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Answer:

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Step-by-step explanation:

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