Answer:
0.118 is the probability someone will spend no more than 30 minutes reading online national news reports.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 49 minutes
Standard Deviation, σ = 16 minutes
We are given that the distribution of time an individual reads is a bell shaped distribution that is a normal distribution.
Formula:
P(no more than 30 minutes)
Calculation the value from standard normal z table, we have,
0.118 is the probability someone will spend no more than 30 minutes reading online national news reports.
Answer:
5c + 1.3d - 6.3
Step-by-step explanation:
Hope this helps.
Answer: 55x + 75 = 350; 5 hours
Step-by-step explanation:
What we know:
- A flat fee is $75
- John charges $55 an hour
- The total charge is $350
We need to write an equation to find how many hours John works.
<em>x </em>will represent hours worked.
55x + 75 = 350
We now need to solve for x.
Subtract 75 from both sides.
55x + 75 - 75 = 350 - 75
Simplify.
55x = 275
Divide 55 from both sides.
55x/55 = 275/55
Simplify.
x = 5
John worked 5 hours.
To check our work, we just plug in our x value!
55(5) + 75
275 + 75 = 350
Answer:
778
Step-by-step explanation:
We have the length of stay as X
X~N (9,(2.4))
The sample is given as n = 1000
P(7<x<14) is what we are trying to get
P(7-9/2.4 < x-9/2.4 < 14-9/2.4)
= P(-0.83<z<2.08)
P(z<2.08)-p(z<-0.83)
When we go to the z table,
0.981-0.0203
= 0.778
0.778x1000
= 778
So in conclusion, 778 of these guests can be expected to stay between 7 and 14 days.
